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IB Math Studies Topic 3 Logic Review

Authored by Samantha Mooneyham

Mathematics

11th Grade

Used 9+ times

IB Math Studies Topic 3 Logic Review
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23 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Express the symbolic statement ~p in words:


p: Vitamin C helps the immune system.

Vitamin C does not help the immune system.

It is true that Vitamin C helps the immune system.

Vitamin A helps the immune system.

Vitamin C may help the immune system.

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Construct a truth table for the given statement s:


​s: (~ p ∨ ​q) → ​(p → ​q)

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3.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Write the statement in symbolic form to determine the truth value for the statement:


Bombay is a city and Brazil is a country.

True

False

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given that p and q each represents a simple​ statement, write the indicated compound statement in its symbolic form.

​p: This is a tiger

​ q: This is a carnivore


If this is not a tiger​, then this is not a carnivore.

~p ⋀ ~q

p → ~q

~q → ~p

~p → ~q

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given that p and q each represents a simple​ statement, write the indicated symbolic statement in words.

p: Roger likes Vanessa

​q: Vanessa likes Roger


~ ​(p ∧ ​q)

Roger likes Vanessa and Vanessa likes Roger.

It is not true that Roger likes Vanessa and Vanessa likes Roger.

Roger likes Vanessa but Vanessa does not like Roger.

Roger does not like Vanessa, but Vanessa likes Roger.

6.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Write the contrapositive of the statement:


If the electricity is out, then I cannot use the computer.

If the electricity is not out, then I can use the computer.

If I cannot use the computer, then the electricity is out.

If I can use the computer​, then the electricity is not out.

If the electricity is out, then I cannot use the computer.

7.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Use grouping symbols to clarify the meaning of the symbolic statement.


p ∨ q → p ↔ q ∧ ~p

p ∨ ​(q → ​p) ↔ ​(q ∧ ~​p)

​(p ∨ ​q) → ​[(p ↔ ​q) ∧ ~​p]

​[(p ∨ ​q) → ​p] ↔ ​(q ∧ ~​p)

p ∨ ​(q → ​p) ↔ ​(q ∧ ~​p)

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