Write Quadratics in different forms

Write the quadratic in standard form. y = (x - 4)(x - 3)

• y = x² - 7x - 12

• y = x² + 7x - 12

• y = x² - 7x + 12

• y = x² + 7x + 12

Write in Standard Form y = 2(x + 5)(x - 1)

• y = 2x² - 8x + 10

• y = 2x² + 8x - 10

• y = 2x² - 8x - 3

• y = 2x² + 8x - 3

Write in Standard Form. y = - 1/2 (x + 4)(x - 2)

• y = -1/2 x² - x + 4

• y = - 1/2 x² + x - 4

• y = -1/2 x² - 2x - 4

• y = -1/2 x² + 2x + 4

Write in Standard Form. y = (x - 2)² + 5

• y = x² - 4x + 9

• y = x² + 4x + 9

• y = 2x² - 4x + 9

• y = 2x² + 4x - 9

Write in Standard Form. y = 2(x + 1)² - 8

• y = 2x² - 4x + 6

• y = 2x² + 4x - 6

• y = x² - 4x - 6

• y = x² + 4x - 6

Write in Standard Form. y = 3/4(x + 2)² + 1

• y = 3/4 x² - 3x - 4

• y = 3/4 x² + 3x - 4

• y = 3/4 x² - 3x + 4

• y = 3/4 x² + 3x + 4

Write in Intercept Form. y = x² - 6x + 9

• y = (x - 9)(x - 1)

• y = (x - 3)²

• y = (x - 3)(x - 3)

• y = (x + 3)(x - 3)

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

Write in intercept form. y = x² - 6x - 16

• y = (x - 10)(x + 6)

• y = (x - 8)(x - 2)

• y = (x + 8)(x - 2)

• y = (x - 8)(x + 2)

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

Calculate the zero value that is to the left of the vertex.

y = x² - 5x + 1

• (4.79, 0)

• (-.21, 0)

• (.21, 0)

• (-4.79, 0)

Calculate the zero value that is to the right of the vertex.

y = x² - 5x + 1

• (4.79, 0)

• (-.21, 0)

• (.21, 0)

• (-4.79, 0)

Tags

CCSS.HSF-IF.C.7A