Systems of Equations

• 
• 
• 
• 

• (2, 1)

• (-3, -1)

• (2, -2)

• None of the above

• (2, 3)

• (3, -2)

• (-1, 14)

• (3, 6)

• No solution

• Infinite solutions

• 1 solution

• 2 solutions

• Substitute –10y + 7 for x in the second equation.

• Substitute 3y + 3 for x in the second equation.

• Multiply the first equation by 3, multiply the second equation by 4, then add the resulting equations together.

• Multiply the first equation by 2, multiply the second equation 5, then add the resulting equations together.

Which is the solution for the system below.

x = -4y + 10

x = 2y – 14

• (-6, 4)

• (4, -6)

• (6, -2)

• (-2, 6)

• (0, -4)

• (4, 0)

• No solution

• Infinite Solutions

Which is the solution to the system shown below.

-3x + 2y = 17

3x – 7y = -37

• (4,-3)

• (-3, 4)

• (-3, -4)

• No Solution

Solve the given system.

4x – 5y = 40

x = 3y + 24

• (-8, 0)

• (0, 8)

• (8, 0)

• (0, -8)

Solve using Substitution

4x = -8y + 20

y = -2x + 7

• (1, 3)

• (-3, 1)

• (3, -1)

• (3, 1)