Circles Review

In the equation (x+5)²+(y+8)²=49, where is the center of the circle?

• (5, 8)

• (8, 5)

• (8, -5)

• (-5, -8)

Tags

CCSS.HSG.GPE.A.1

In the equation (x+4)²+(y-4)²=16, what is the radius of the circle?

• 16

• 4

• 8

• 2

Tags

CCSS.HSG.GPE.A.1

What is the equation of the circle?

• (x+5)² + (y+8)² = 25

• (x-5)² + (y-8)² = 25

• (x+8)² + (y+5)² = 5

• (x+5)² + (y+8)² = 5

Tags

CCSS.HSG.GPE.A.1

Change the following equation to standard form
x²+y²-4x+12y-8=0

• (x+2)²+(y-6)²=48
• (x-2)²+(y+6)²=48
• (x-6)²+(y-2)²=48
• (x+2)²+(y-6)²=48

Tags

CCSS.HSG.GPE.A.1

Find the center and radius of the circle: x²+y²+14x-2y=-1

• center= (-7, 2) radius= 3

• center= (-7, 1) radius= 7

• center= (-4, 1) radius= 5