MC & FR Momentum

• Δp₂= 0.3 kg⋅m/s and a₂= 3 m/s²

• Δp₂= 0.3 kg⋅m/s and a₂= 15 m/s²

• Δp₂= 1.5 kg⋅m/s and a₂= 3 m/s²

• Δp₂= 1.5 kg⋅m/s and a₂= 15 m/s²

A 1.0 kg lump of clay is sliding to the right on a frictionless surface with speed 2 m/s. It collides head on and sticks to a 0.5 kg metal sphere that is sliding to the left with speed 4 m/s. What is the kinetic energy of the combined objects after the collision?

• 6 J

• 4 J

• 2 J

• 0 J

• Only conservation of momentum, because the momentum lost by one cart is gained by the other and there is only one unknown quantity.

• Both conservation of mechanical energy and conservation of momentum, because both principles apply to any collision.

• Both conservation of mechanical energy and conservation of momentum, because neither cart changes direction.

• Either conservation of momentum or conservation of mechanical energy, because only one equation is required to solve for the one unknown variable.

• 12 kg⋅m/s

• 48 kg⋅m/s

• 60 kg⋅m/s

• 96 kg⋅m/s

• 52 kg⋅m/s

• 6 kg⋅m/s

• -6 kg⋅m/s

• -18 kg⋅m/s

• 30 m/s

• 50 m/s

• 70 m/s

• 90 m/s

• The momentum of the block has decreased to zero at time t_1.

• The momentum of the block has increased by approximately ½F₀t₁

• The momentum of the block has decreased by approximately ½F₀t₁

• The change in momentum cannot be determined without knowing the distance by which the force probe compressed the block.

• Kinetic energy increases

  Speed = 2 m/s

• Kinetic energy increases

  Speed= 3.2 m/s

• Kinetic energy decreases

  Speed= 2 m/s

• Kinetic energy decreases

  Speed= 3.2 m/s