Geometry

Which formula shows how to find the perimeter of this rectangle?

• Perimeter = (3 × width) + (3 × length)

• Perimeter = (2 × width) + (2 × length)

• Perimeter = length + width

The area of the rectangle from question #1 is

• 156 cm

• 3168 cm sq

• 312 cm sq

• 2640 cm

What is the perimeter of the rectangle from question #1?

• 312 cm

• 156 cm

• 3168 cm sq

• 2640 cm

Which formula shows how to find the area of this rectangle?

• Area = (2 × width) + (2 × length)

• Area = length + width

• Area = length × width

• Area= add all the sides together

Kherington has sorted a collection of shapes and labeled them.

• Kherington is correct because all the shapes on the left have 2 pairs of parallel lines, but no right angles. The ones on the right all have at least one right angle, but none of them have parallel sides. The ones in the middle have both.

• Kherington is correct because all the shapes on the left are regular polygons. The shapes on the right are not regular polygons and the ones in the middle are quadrilaterals.

• Kherington is incorrect because all the shapes on left have 2 acute angles and 2 obtuse angles. All the shapes on the right 2 right angles and 2 obtuse angles. The shapes in the middle are rectangles.

• Kherington is incorrect is because all the shapes have at 2 pairs of parallel sides. The shapes in the middle have perpendicular lines.

What reasons would Kherington give for the 2 shapes in the middle?

• Both of the shapes are rectangles

• Both have 2 pairs of parallel and 4 right angles

• Both figures are parallelograms

• Both figures are quadrilaterals

Kherington says that she can’t put a right triangle in either of the groups. Do you agree? Explain your answer

• Yes I agree because a right triangle has 3 sides and wouldn't fit in either group.

• No I disagree because a right triangle would fit in the group on the right side because it has at least 1 right angle.

• Yes I agree because a right triangle has no parallel sides and wouldn't fit in either group.

• No I disagree because a right triangle has 1 pair of parallel sides and would fit in the group on the left.