Addition Rule - Probability

If you draw one card from a standard deck, what is the probability of drawing a 5 or a diamond?

• 2/52

• 4/52

• 4/13

• 26/52

Tags

CCSS.HSS.CP.A.1

CCSS.HSS.CP.B.7

Find the probability of choosing a card at random that is a spade OR a 7

• 1/52

• 1/13

• 4/13

• 17/52

Tags

CCSS.HSS.CP.A.1

CCSS.HSS.CP.B.7

If you roll one die, what is the probability of getting an even number or a multiple of 3?

• 1/3
• 2/3
• 1/2
• 1/6

Tags

CCSS.HSS.CP.A.1

CCSS.HSS.CP.B.7

What is the probability of spinning green or blue?

• 0
• 5/12
• 1/2
• 3/4

Tags

CCSS.HSS.CP.A.1

CCSS.HSS.CP.B.7

find the probability of choosing a student at random that plays an instrument OR a sport

• 1/2
• 13/20
• 21/20
• 4/5

Tags

CCSS.HSS.CP.A.1

CCSS.HSS.CP.A.4

CCSS.HSS.CP.B.7

The table above displays the 100 senators of the 112th U.S Congress on January 5, 2011, classified by political party affiliation and gender. A senator is selected at random from this group. Compute the following probability: The senator is a Democrat or a female.

• .42

• .56

• .47

• .53

Tags

CCSS.HSS.CP.A.1

CCSS.HSS.CP.B.7

The table above displays the 100 senators of the 112th U.S Congress on January 5, 2011, classified by political party affiliation and gender. A senator is selected at random from this group. Compute the following probability: The senator is an Democrat or an Independent.

• .42

• .53

• .002

• .50

Tags

CCSS.HSS.CP.A.1

CCSS.HSS.CP.B.7

A poll was taken of 121,973 people in the United States aged 15-44 to determine their health insurance status. The participants were classified by gender and by type of insurance coverage. The results were as follows. A person is selected at random. Compute the following probability: The person is female or has private insurance.

• .8417

• .0781

• .7657

• .6876

Tags

CCSS.HSS.CP.A.1

CCSS.HSS.CP.B.7

A poll was taken of 121,973 people in the United States aged 15-44 to determine their health insurance status. The participants were classified by gender and by type of insurance coverage. The results were as follows. A person is selected at random. Compute the following probability: The person has private insurance or medicaid.

• .8417

• .0781

• .7657

• .6876

Tags

CCSS.HSS.CP.A.1

CCSS.HSS.CP.B.7

CCSS.HSS.IC.A.1

CCSS.HSS.IC.B.4

Which of the following shows how to determine P(packers or male)?

• 75/150 + 90/150 - 50/150
• 75/150 + 35/150 - 25/150
• 50/150 + 40/150 + 25/150
• 90/150 + 50/150 - 75/150

Tags

CCSS.HSS.CP.A.1

CCSS.HSS.CP.B.7