Solving Systems by Substitution

Solve the system of equations using substitution:
y = 2x + 5
2x + 2y = 4

• (1, 7)
• (7, 1)
• (2, 9)
• (-1, 3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

These two lines intersect at _____.

• (4, -2)
• (4, 2)
• (-2, 4) 
• No solution

Tags

CCSS.8.EE.C.8A

The solution is:

• (4, 3)
• (3, 4)
• (-4, 3)
• No solution

Tags

CCSS.8.EE.C.8A

How many solutions will this system have? 

• No solution
• One Solution
• I Don't Know
• Infinitely Many Solutions

Tags

CCSS.8.EE.C.8A

6x + y = -1
y = -3x - 4

• (3, 1)
• (1, 7)
• (-3, 1)
• (1, -7)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

y = -3x + 11
5x + y = 21

• (1, -5)
• (1, 5)
• (-4, 5)
• (5, -4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

y = -6x + 5
-2x + y = 5

• (-3, -6)
• (-6, 3)
• (0, 5)
• (-3, 5)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

y = -2x + 18
y = 8

• (5, 8)
• (-5, 8)
• (2, 8)
• (-2, 8)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve:
y = 2x -11
-3y = -6x -15

• (-1.5,-4)
• (1.5,4)
• No solution (parallel lines)
• Infinitely many solutions

Tags

CCSS.8.EE.C.8B

x + 2y = 2
x = -4y + 2

• (-3, 0)
• (0, 2)
• (-3, -2)
• (2, 0)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6