HC VSEPR & Polarity Check-In

HC VSEPR & Polarity Check-In

10th - 12th Grade

24 Qs

quiz-placeholder

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HC VSEPR & Polarity Check-In

HC VSEPR & Polarity Check-In

Assessment

Quiz

Chemistry

10th - 12th Grade

Medium

NGSS
HS-PS1-3, HS-PS1-1, HS-PS1-2

+1

Standards-aligned

Created by

Matthew Owen

Used 4+ times

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24 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

According to VSEPR, molecules adjust their shapes to keep which of the following as far away as possible?

Pairs of valence electrons

Inner shell electrons

Mobile Electrons

Electrons closest to the nucleus

Answer explanation

According to VSEPR theory, molecules adopt shapes that minimize repulsion between electron pairs. Therefore, they adjust to keep pairs of valence electrons as far apart as possible, which is crucial for determining molecular geometry.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What geometry is this? (The balloon-like shapes are lone pairs!)

Linear

Trigonal Pyramidal

Bent

Tetrahedral

Answer explanation

The geometry is bent because the lone pairs (balloon-like shapes) repel the bonding pairs, causing the molecule to adopt a bent shape rather than a linear or tetrahedral arrangement.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What is the geometry of this molecule?

Tetrahedral

Linear

Trigonal Pyramidal

Trigonal Planar

Answer explanation

The molecule has a tetrahedral geometry, which occurs when a central atom is bonded to four other atoms with no lone pairs, resulting in bond angles of approximately 109.5 degrees.

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Which molecule would have this shape (linear)?

BF3

CH4

PCl3

CO2

Answer explanation

CO2 has a linear shape due to its two double bonds and no lone pairs on the central carbon atom, resulting in a bond angle of 180 degrees. In contrast, BF3, CH4, and PCl3 have different geometries.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What molecule could this be? (Look at how many domains it has!)

BF3

CH4

H2O

CO2

Answer explanation

BF3 has three bonding domains around the boron atom, indicating it is a trigonal planar molecule. In contrast, CH4, H2O, and CO2 have different numbers of domains, making BF3 the correct choice.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

SiCl4 has what shape?

Trigonal pyramid

bent

tetrahedral

Trigonal planar

Answer explanation

SiCl4 has a tetrahedral shape due to its four bonding pairs of electrons around the central silicon atom, which repel each other equally, resulting in a three-dimensional arrangement.

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What Shape would BH3 form?

Trigonal Pyrimidal

Trigonal Planar

Tetrahedral

Bent

Answer explanation

BH3 has three hydrogen atoms bonded to a central boron atom with no lone pairs, resulting in a trigonal planar shape. The bond angles are approximately 120 degrees, confirming the trigonal planar geometry.

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