Solving Quadratics with Complex Solutions

Solve x² - 5x + 10 = 0

• (5 - i√15)/2  ,  (5 + i√15)/2
• (5 - √15)/2  ,  (5 + √15)/2
• (5 - i√65)/2  ,  (5 + i√65)/2
• (5 - √65)/2  ,  (5 + √65)/2

Tags

CCSS.HSA.REI.B.4

CCSS.HSN.CN.A.1

CCSS.HSN.CN.A.2

Solve -2x² + 4x = 9

• (2 - i√14)/2   ,   (2 + i√14)/2
• (2 - i√-56)/2   ,   (2 + i√-56)/2
• (2 - i√-14)/2   ,   (2 + i√-14)/2
• (2 - √14)/2   ,   (2 + √14)/2

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

3x²-9x+7=0

• (3+2i√5)/2 and (3-2i√5)/2
• 9+i√3  and 9-i√3
• (9+i√3)/6 and (9-i√3)/6
• 3+2i√5 and 3-2i√5

6n²-9n+12=0

• (3+i√23)/4 and (3-i√23)/4

• 3+i and 3-i

• 4+3i and 4-3i

• (4+i√22)/2 and (4-i√22)/2

  x²+10x+29=0

• -5+2i and -5-2i
• 5+2i and 5-2i
• -2+5i and -2-5i
• 2+5i and 2-5i

Solve by completing the square.
x² +12x = 5

• X = 6 + √41 or  6 − √41
• X= 35 or 47
• X = −6 + √41 or  −6 − √41
• X = √35 or √47

Tags

CCSS.HSA.REI.B.4

Solve by completing the square:
k² − 12k + 23 = 0

• {6 + √13, 6 - √13}
• {-6 + √13, -6 - √13}
• {6 + √59, 6 - √59}
• {-6 + √59, -6 - √59}

Tags

CCSS.HSA-REI.B.4B

Which is a solution to (½)x² + 8 = 0

• - 4i
• 16i
• - 16i
• 1

Tags

CCSS.HSA.REI.B.4

CCSS.HSN.CN.A.1

CCSS.HSN.CN.A.2