Math Models - Solve Quadratics by Factoring

What is the first step in solving (x + 2)(x - 3) = 0 ?

• Plug in zero for x

• Solve for x

• FOIL

• Set each binomial factor equal to zero

Which equation matches these solutions? x = 5 and x = -7

• (x+5)(x-7) = 0

• (x-5)(x+7) = 0

• (x+5)(x+7) = 0

• (x-5)(x-7) = 0

Factor the quadratic then find the zeros 2x² + 2x - 12?

• (-2, 0) and (3, 0)

• (2, 0) and (3,0)

• (2, 0) and (-3,0)

• (0, 2) and (0, -3)

Factor and find the roots of this quadratic.

• b=4/5, b=3

• b=4, b=-3

• b=1/5, b=3

• b=4/5, b=-3

What are the factors AND solutions of x² + 2x – 3 = 0

• (x - 2)(x + 1); x=2, x=-1
• (x + 1)(x - 3); x=-1, x=3
• (x + 2)(x - 1); x=-2, x=1
• (x - 1)(x + 3); x=1, x=-3

Solve by factoring:

x² - 9x = 0

• x = 9

• x = 0 or x = 9

• x = -9 or x = 0

• x = -9

Solve
6x² + 17x + 12 = 0

• x = -4/3, x = -3/2
• x = 9, x = 8
• x = 4, x = 3
• x = -4, x = -3

Solve
 2x² - 3x - 2 = 0

• x = 1, x = -1
• x = -1/2, x = 2
• x = 1/2, x = 2
• x = 1/2, x = 1

Solve
5x² - 28x + 32 = 0

• x = 10/3, x = -6
• x = 8, x = 4/5
• x = 8/5, x = 4
• x = 8/5, x = -7

Solve
 3x² + 5x - 12 = 0

• x = -4/3, x = 3
• x = 4/3, x = -3
• x = -1, x = 4
• x = 1, x = -4