Graphing Circles on a coordinate plane

What is the standard equation of a circle?

• (x-k)² + (y-h)² = r²

• (x+h)² + (y+k)² = r²

• (x-h)² + (y-k)² = r²

• (k-x)² + (h-y)² = r²

Tags

CCSS.HSG.GPE.A.1

What does (h,k) stand for in the standard circle equation?

• (h,k) is the center of the circle

• (h,k) is a point on the circle.

• (h,k) is a point that we guess and find

• (h,k) is the distance of the circle

Tags

CCSS.HSG.GPE.A.1

In the equation (x-3)²+(y+4)²=121, the radius of the circle is

• 242
• 11
• 121
• 22

Tags

CCSS.HSG.GPE.A.1

What is the equation of a circle with radius 2 and center (3, 4)?

• (x+3)² + (y+4)² = 2
• (x-3)² + (y-4)² = 2
• (x+3)² + (y+4)² = 4
• (x-3)² + (y-4)² = 4

Tags

CCSS.HSG.GPE.A.1

What is the equation of the circle?

• (x+1)² + (y +1)² = 3
• (x+1)² + (y -1)² = 3
• (x+1)² + (y +1)² = 9
• (x-1)² + (y -1)² = 9

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

CCSS.HSG.GPE.A.1

What are the coordinates of the center and the radius of the circle with equation:
(x - 4)² + (y - 3)² = 25 ?

• Center (4,3)
  Radius = 5 units
• Center (4,3)
  Radius = 25 units
• Center (-4,-3)
  Radius = 25 units
• Center (-4,-3)
  Radius = 5 units

Tags

CCSS.HSG.GPE.A.1

In the equation (x-3)²+(y-2)²=16, the center of the circle is...

• (3,2)
• (-3, -2)
• (-2, -3)
• (2, 3)

Tags

CCSS.HSG.GPE.A.1

The diameter of a circle has length 12. The center is at (-5, 2). Give the equation of the circle.

• (x + 5)² + (y - 2)² = 144

• (x - 5)² + (y + 2)² = 36

• (x + 5)² + (y - 2)² = 36

• (x - 5)² + (y + 2)² = 12

Tags

CCSS.HSG.GPE.A.1

The point (3,3) is on a circle whose center is at (-1,3). Write the standard form of the equation of the circle.

• (x-3)²+(y-3)²=4

• (x-3)²+(y-3)²=16

• (x+1)²+(y-3)²=9

• (x+1)²+(y-3)²=16

Tags

CCSS.HSG.GPE.A.1

Write the equation of a circle with its diameter whose endpoints are (2,7) and (4,-3). Hint: first find the center of the circle using midpoint formula.

• (x-3)²+(y-2)²=26

• (x+3)²+(y+2)²=26

• (x+1)²+(y-5)²=13

• (x+1)²+(y-5)²=89

Tags

CCSS.HSG.GPE.A.1