Equations of Circles

In the equation (x-3)²+(y-2)²=16, the center of the circle is...

• (3,2)
• (-3, -2)
• (-2, -3)
• (2, 3)

Tags

CCSS.HSG.GPE.A.1

In the equation (x+2)²+(y-3)²=4, the radius of the circle is...

• 4
• 2
• 3
• 16

Tags

CCSS.HSG.GPE.A.1

In the equation (x-4)²+(y-3)²=25, the radius is

• 4
• 3
• 5
• 25

Tags

CCSS.HSG.GPE.A.1

In the equation (x+2)²+(y-3)²=4, the center of the circle is at...

• (-2, 3)
• (-3, 2)
• (2, -3)
• (3, -2)

Tags

CCSS.HSG.GPE.A.1

In the equation (x-3)²+(y+4)²=121, the center of the circle is at...

• (3, -4)
• (-3, 4)
• (4, 3)
• (-4, -3)

Tags

CCSS.HSG.GPE.A.1

What is the equation of a circle with radius 2 and center (3, 4)?

• (x+3)² + (y+4)² = 2
• (x-3)² + (y-4)² = 2
• (x+3)² + (y+4)² = 4
• (x-3)² + (y-4)² = 4

Tags

CCSS.HSG.GPE.A.1

What is the equation of a circle with radius 4 and center (0, 8)?

• x² + (y-8)² = 16
• (x-8)² + y² = 4
• x² + (y-8)² = 4
• x² + (y+8)² = 16

Tags

CCSS.HSG.GPE.A.1

What is the center of the circle with equation x² + y² = 1?

• (1, 1)
• (0, 0)
• not enough information

Tags

CCSS.HSG.GPE.A.1

See Picture

• A
• B
• C
• D

Tags

CCSS.HSG.GPE.A.1

The endpoints of a diameter of a circle are (3,1) and (9,5).Find the equation of the circle?

• (x−6)²+(y−3)²=13
• (x−3)²+(y−6)²=13²
• (x−5)²+(y−9)²=13
• (x−9)²+(y−5)²=169/4

Tags

CCSS.HSG.GPE.A.1