Exponential Growth and Decay

Caiden earned $475 from mowing lawns last summer.He deposited this money in an account that pays an interest rate of 3.8% compounded annually. What will be his balance after 15 years?

• $827.52

• $831.10

• $839.45

• $846.80

Semi-Annually means how many times a year?

• 4 
• 2
• 1
• 6

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CCSS.3.MD.A.1

Anne deposited $500 in an

account that earns 6% interest compounded continuously.

Shelly deposited $500 in an account that earns 6% annual interest

compounded monthly. They leave the

money in the account for 4 years. Which

statement is true about the two investments after 4 years?

• Shelly will have $1.38 more in her account

  than Anne has in her account.

• They will have the same

  amount in their accounts.

• Anne will have $0.38 more

  in her account than Shelly has in her account.

• Anne will have $11.24 more in

  her account than Shelly has in her account.

Riley invested $1,000 in savings bonds. If the bonds earn 6.75% interest compounded semi-annually, how much total will Riley earn in 15 years?

• $1,584.62
• $2,651.39
• $2,706.86
• $1,825.10

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CCSS.HSF.LE.A.2

CCSS.HSF.LE.A.1

CCSS.HSA.CED.A.1

CCSS.HSF.BF.A.1

Compounded Continuously an investment of  $400 at a rate of 35% for 2 years

• $280
• $680
• $1,034.47
• $805.50

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CCSS.HSF.LE.A.2

CCSS.HSF.LE.A.1

CCSS.HSA.CED.A.1

CCSS.HSF.BF.A.1

If $1,000 is invested at 16% interest, compounded continuously, for five years, what is the ending balance?

• $1,225,54
• $2,225.54
• $22,255.40
• $225.54

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CCSS.HSF.LE.A.2

CCSS.HSF.LE.A.1

CCSS.HSA.CED.A.1

CCSS.HSF.BF.A.1

CCSS.HSF.LE.B.5

The growth factor for this table is 

• 2
• 4
• 12
• 144

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CCSS.HSF-LE.A.1A

The equation for this table is 

• y = 100(2^x)
• y = 2^x
• y = 2x + 100
• y = 100^x

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CCSS.HSF.LE.A.2

There were 417 cell phones sold at an electronics store in January. Since then, cell phone sales at this store have increased at a rate of 3.75% per month. At this rate of growth, which function can be used to determine the monthly cell phone sales x months after January?

• f(x) = 417(3.75)^x
• f(x) = 417(0.0375)^x
• f(x) = 417(1.0375)^x
• f(x) = 417(1.375)^x

Tags

CCSS.HSF.LE.A.2

• The graph represents an exponential growth situation.
• Eventually, the car will be worth exactly $0.
• The starting value of the car was $12,000.
• The range for the situation is y ≥ 0.

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CCSS.HSF.LE.A.2

CCSS.HSF.LE.A.1

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7