Antiderivative

Given v(t) = x^-9, find the general equation for the antiderivative.

• (1/8)x^-8 + C
• (-1/8)x^-8 + C
• (1/10)x¹⁰
• (-1/8)x^-8

∫(4 - 18x)dx

• F(x) = -18
• F(x) = 4x - 9x²
• F(x) = 4x - 9x² + C
• F(x) = (4 - 18x)² /2 + C

∫ t⁶ dt

• 6t⁵
• 6t⁵ + C
• 1/7 t⁷ + C
• t⁷ + C

∫ - sinx dx

• -cos x + C
• cos x + C
• tan x + C
• 1/√1- x²

∫(4/x - e^x ) dx

• 4ln x - e^x
• 4 ln x + e^x + C
• 4 ln x - e^x + C
• 4/x²  - 4e^x + C

∫ x(x² - 4) dx

• x²/2(x³/3 - 4x) + C
• .25x⁴ -2x² + C
• 3x²- 4 + C
• x⁴ - 4x² + C

∫25sec²x dx

• 25 secx tanx + C
• 25 tanx + C
• -25 tanx + C
• -25 sec x + C

∫sec²x dx =

• -cotx + C
• cotx + C
• -tanx + C
• tanx + C

Find the particular solution: f'(x) = 6x, f(-3) = 20

• 3x - 7

• 3x² - 7

• 3x² + 7

• 2x² + 2

Find the particular solution: f"(x) = 2, f'(1) = 4, f(1) = 8

• 2x + c

• 2x² + 2x + 4

• x² + 2x + 5

• x² + 2x + c