Solving By Factoring

Solve for the values of x:
(x + 2)(x - 3) = 0

• { 2, 3 }
• { -2, -3 }
• { 2, 3 }
• { -2, 3 }

Tags

CCSS.HSA-REI.B.4B

Solve for the values of x:
(2x - 1)(x + 4) = 0

• { 1/2, -4 }
•  { 1/2, 4 }
• { 2, -4 }
• { -2, 4 }

Tags

CCSS.HSA-REI.B.4B

Solve for the values of x:
(2x + 5)(5x - 2) = 0

• { -5/2, -2/5 }
• { -5/2, 2/5 }
• { 5/2, 2/5 }
• { 5/2, -2/5 }

Tags

CCSS.HSA-REI.B.4B

Solve and find your x-intercepts:
0=x(x - 6)

• x=0 and x=-6
• x=1 and x=-6
• x=0 and x=6
• x=6

Tags

CCSS.HSA-REI.B.4B

Solve and find your zeros:
z(z - 15)=0

• z=0 and z=15
• z=0 and z=-15
• z=-15
• z=15

Tags

CCSS.HSA-REI.B.4B

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

Tags

CCSS.HSA-REI.B.4B

Solve for the values of x:
(x - 3)(x + 6) = 0

• { -3, -6 }
• { 3, -6 }
• { -3, -6 }
• { 3, 6 }

Tags

CCSS.HSA-REI.B.4B

What are the solutions to this equation?

(x-3)(x-2)=0

• x=3,-2

• x=-3,2

• x=2,3

• x=-3,-2

Tags

CCSS.HSA-REI.B.4B

In the equation

(x + 2)(x - 3) = 0, the binomials are called...?

• Factors

• Products

• Multiples

• Zeros

Tags

CCSS.HSA.APR.B.2

Solve for the values of x:
(2x - 1)(x + 4) = 0

• { 1/2, -4 }
•  { 1/2, 4 }
• { 2, -4 }
• { -2, 4 }

Tags

CCSS.HSA-REI.B.4B