Honors Algebra 2 Final Exam Review #2

Simplify: 
(7 + 2i)(9 - 6i)

• 75-24i
• 63 - 24i  - 12i²
• 51 - 24i
• 58 + 60i

Tags

CCSS.HSN.CN.A.2

Multiply: 
(4 – 3i)(7 + 2i)

• A.  22 - 13i
• B.  28 - 19i
• C.  34 - 13i
• D.  -34 - 29i

Tags

CCSS.HSA.APR.A.1

Write the polynomial in standard form given the following zeros. x = -2, 1, 4

• f(x) = (x+2)(x-1)(x-4)

• f(x) =x³ - 3x² - 6x + 8

• f(x) = x³ + 8

• f(x) = x³ - 3x² + 8

Tags

CCSS.HSA.APR.B.3

Build a Polynomial with the following Zeros:

4, 5, 6, 7

• x⁴ - 22x³ + 89x² + 638x + 730

• x⁴ - 12x³ - 179x² - 638x + 540

• x⁴ - 22x³ + 179x² - 638x + 840

• x⁴ - 13x³ + 179x² - 638x + 640

Tags

CCSS.HSA.APR.B.3

Solve

8x³+125=0

• x=-5/2, x=(-5±5i√3)/4

• x=-5/2, x=(5±5i√3)/4

• x=-2/5, x=(-5±5i√3)/4

• x=-2/5, x=(5±5i√3)/4

Tags

CCSS.8.EE.A.2

x³ - 27

• (x - 4)(x² + 4x + 16)
• (x + 3)(x² - 4x + 16)
• (x - 1)(x² + 1x + 1)
• (x - 3)(x² + 3x + 9)

Tags

CCSS.HSA.APR.C.4

if f(x) = x³+8x+24, then find f(-2) using synthetic division.

• 12
• 8
• 0
• -6

Tags

CCSS.HSA.APR.D.6

Use synthetic division to determine f(-3), if
f(x)= (3x³ -5x² -4x +1).

• -25
• 25
• 113
• -113

Tags

CCSS.HSA.APR.D.6

• 9

• -9

• 7

• -7

Tags

CCSS.HSA.REI.A.2

• 3

• 2

• -3

• -2

Tags

CCSS.HSA.REI.A.2