Unit 8 Circles Review

In the equation (x-3)²+(y-2)²=16, the center of the circle is...

• (3,2)
• (-3, -2)
• (-2, -3)
• (2, 3)

Tags

CCSS.HSG.GPE.A.1

In the equation (x-3)²+(y+4)²=121, the radius of the circle is

• 242
• 11
• 121
• 22

Tags

CCSS.HSG.GPE.A.1

Find the measure of angle ABD.

• 14
• 51
• 37
• 65

Tags

CCSS.HSG.C.A.2

In the diagram, a tangent and a line drawn to the point of tangency form a right triangle. Solve for "?"

• -15

• 6

• 15

• 14

Tags

CCSS.HSG.C.A.2

What is the measure of arc AB?

• 120°

• 60°

• 240°

• 80°

Tags

CCSS.HSG.C.B.5

• A
• B
• C
• D

Tags

CCSS.HSG.C.A.2

Change the following equation to standard form
x²+y²-4x+12y-8=0

• (x+2)²+(y-6)²=48
• (x-2)²+(y+6)²=48
• (x-6)²+(y-2)²=48
• (x+2)²+(y-6)²=48

Tags

CCSS.HSG.GPE.A.1

Determine the center and radius:
x² + y² - 10x + 8y -8 = 0

• C = (5,-4) r = 7
• C = (-5,4) r = 7
• C = (-4,5) r = 49
• C = (5,-4) r = 49

Tags

CCSS.HSG.GPE.A.1

• 9
• 10
• 15
• 14

Tags

CCSS.HSG.C.A.2

• A
• B
• C
• D

Tags

CCSS.HSG.C.A.2