Solve for x: ∣ x + 6 ∣ = 11 \left|x+6\right|=11 ∣ x + 6 ∣ = 1 1

x = 5 O R x = − 17 x=5\ \ \ \ \ OR\ \ \ \ \ x=-17 x = 5 O R x = − 1 7

x = − 6 O R x = 11 x=-6\ \ \ \ OR\ \ \ \ x\ =\ 11 x = − 6 O R x = 1 1

x = − 5 O R x = 17 x=-5\ \ \ \ OR\ \ \ \ \ x\ =\ 17 x = − 5 O R x = 1 7

Solve: ∣ 2 x − 1 ∣ = − 4 \left|2x-1\right|=-4 ∣ 2 x − 1 ∣ = − 4

x = 1 2 O R x = − 4 x=\frac{1}{2}\ \ \ \ OR\ \ x\ =\ -4 x = 2 1 O R x = − 4

x = − 3 2 O R x = 5 2 x=-\frac{3}{2}\ \ OR\ \ x\ =\ \frac{5}{2} x = − 2 3 O R x = 2 5

x = 5 2 O R x = − 3 2 x=\frac{5}{2}\ \ OR\ \ x\ =\ -\frac{3}{2} x = 2 5 O R x = − 2 3

Solve for x: ∣ 3 x − 6 ∣ − 9 = − 3 \left|3x-6\right|-9=-3 ∣ 3 x − 6 ∣ − 9 = − 3

x = 0 x=0 x = 0 OR x = 4 x=4 x = 4

x = 2 x=2 x = 2 OR x = − 2 x=-2 x = − 2

x = − 4 x=-4 x = − 4 OR x = 4 x=4 x = 4

∣ x ∣ = 5 \left|x\right|=5 ∣ x ∣ = 5 Solve for x:

x = 5 O R x = − 5 x=5\ \ \ OR\ \ \ x\ =\ -5 x = 5 O R x = − 5

Solve: ∣ x − 12 ∣ − 3 = 11 \left|x-12\right|-3=11 ∣ x − 1 2 ∣ − 3 = 1 1

x = − 2 O R x = 26 x=-2\ \ \ OR\ \ \ x\ =\ 26 x = − 2 O R x = 2 6

x = − 2 O R x = − 26 x=-2\ \ \ OR\ \ \ x=-26 x = − 2 O R x = − 2 6

x = 3 O R x = 25 x=3\ \ \ OR\ \ \ x\ =\ 25 x = 3 O R x = 2 5

x = 4 O R x = − 7 x\ =\ 4\ \ \ OR\ \ \ x\ =\ -7 x = 4 O R x = − 7

Solve for x: − 2 ∣ 5 x − 1 ∣ − 3 = − 11 -2\left|5x-1\right|-3=-11 − 2 ∣ 5 x − 1 ∣ − 3 = − 1 1

x = − 3 5 O R x = 1 x=-\frac{3}{5}\ \ \ OR\ \ \ x\ =\ 1 x = − 5 3 O R x = 1

x = 3 5 O R x = − 1 x=\frac{3}{5}\ \ OR\ \ x\ =\ -1 x = 5 3 O R x = − 1

x = − 2 3 O R x = 5 x=-\frac{2}{3}\ \ OR\ \ x\ =\ 5 x = − 3 2 O R x = 5

x = 2 3 O R x = − 5 x=\frac{2}{3}\ \ \ OR\ \ \ x\ =\ -5 x = 3 2 O R x = − 5

Solve: 4 ∣ 2 x + 7 ∣ = 16 4\left|2x+7\right|=16 4 ∣ 2 x + 7 ∣ = 1 6

x = − 5.5 O R x = − 1.5 x=-5.5\ \ \ OR\ \ x\ =\ -1.5 x = − 5 . 5 O R x = − 1 . 5

x = 5.5 O R x = 1.5 x=5.5\ \ \ OR\ \ \ x\ =\ 1.5 x = 5 . 5 O R x = 1 . 5

x = 2.4 O R x = − 0.4 x=2.4\ \ \ OR\ \ x\ =\ -0.4 x = 2 . 4 O R x = − 0 . 4

x = − 2.4 O R x = 0.4 x=-2.4\ \ \ OR\ \ \ x\ =\ 0.4 x = − 2 . 4 O R x = 0 . 4

Solve for x: ∣ − 3 x ∣ = 15 \left|-3x\right|=15 ∣ − 3 x ∣ = 1 5

x = − 5 O R x = 5 x=-5\ \ \ OR\ \ \ x\ =\ 5 x = − 5 O R x = 5

x = − 12 O R x = 12 x=-12\ \ \ OR\ \ \ x\ =\ 12 x = − 1 2 O R x = 1 2

x = 8 O R x = − 8 x\ =\ 8\ \ \ OR\ \ x\ =\ -8 x = 8 O R x = − 8

#1.4 Solving Absolute Value Equations

Authored by Stephanie DiBari

Mathematics

8th - 9th Grade

CCSS covered

Used 119+ times

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MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve for x:
$\left|x+6\right|=11$

$x=-6\ \ \ \ OR\ \ \ \ x\ =\ 11$

No Solution

$x=5\ \ \ \ \ OR\ \ \ \ \ x=-17$

$x=-5\ \ \ \ OR\ \ \ \ \ x\ =\ 17$

Tags

CCSS.HSA.REI.B.3

CCSS.HSA.REI.A.1

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve:

$\left|2x-1\right|=-4$

$x=\frac{1}{2}\ \ \ \ OR\ \ x\ =\ -4$

No Solution

$x=-\frac{3}{2}\ \ OR\ \ x\ =\ \frac{5}{2}$

$x=\frac{5}{2}\ \ OR\ \ x\ =\ -\frac{3}{2}$

Tags

CCSS.HSA.REI.B.3

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve for x:

$\left|3x-6\right|-9=-3$

No Solution

$x=0$ OR $x=4$

$x=2$ OR $x=-2$

$x=-4$ OR $x=4$

Tags

CCSS.HSA.REI.B.3

CCSS.HSA.REI.A.1

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

$\left|x\right|=5$ Solve for x:

$x=5\ \ \ OR\ \ \ x\ =\ -5$

$x=5$

$x=-5$

No Solution

Tags

CCSS.HSA.REI.B.3

CCSS.HSA.REI.A.1

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve:
$\left|x-12\right|-3=11$

$x=-2\ \ \ OR\ \ \ x=-26$

$x=-2\ \ \ OR\ \ \ x\ =\ 26$

$x=3\ \ \ OR\ \ \ x\ =\ 25$

$x\ =\ 4\ \ \ OR\ \ \ x\ =\ -7$

Tags

CCSS.HSA.REI.B.3

CCSS.HSA.REI.A.1

CCSS.HSA.CED.A.1

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve for x:

$-2\left|5x-1\right|-3=-11$

$x=-\frac{3}{5}\ \ \ OR\ \ \ x\ =\ 1$

$x=\frac{3}{5}\ \ OR\ \ x\ =\ -1$

$x=-\frac{2}{3}\ \ OR\ \ x\ =\ 5$

$x=\frac{2}{3}\ \ \ OR\ \ \ x\ =\ -5$

Tags

CCSS.HSA.REI.B.3

CCSS.HSA.REI.A.1

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve:

$4\left|2x+7\right|=16$

$x=-5.5\ \ \ OR\ \ x\ =\ -1.5$

$x=5.5\ \ \ OR\ \ \ x\ =\ 1.5$

$x=2.4\ \ \ OR\ \ x\ =\ -0.4$

$x=-2.4\ \ \ OR\ \ \ x\ =\ 0.4$

Tags

CCSS.HSA.REI.B.3

CCSS.HSA.REI.A.1

CCSS.HSA.CED.A.1

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

On a soundtrack the minimum length of a song is 3 minutes and the maximum length is 5 minutes. Write an absolute value equation that represents this minimum and maximum.

$\left|x-4\right|=1$

$\left|x-1\right|=4$

$\left|x-3\right|=5$

$\left|x-5\right|=3$

Tags

CCSS.HSA.CED.A.3

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve for x:

$\left|x+3\right|=-2$

No Solution

$x=5\ \ \ OR\ \ \ x\ =\ -3$

$x=-5\ \ \ OR\ \ \ x\ =\ 3$

$x=-5\ \ \ OR\ \ \ x\ =\ -3$

10.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve for x:

$\left|-3x\right|=15$

$x=-5\ \ \ OR\ \ \ x\ =\ 5$

No Solution

$x=-12\ \ \ OR\ \ \ x\ =\ 12$

$x\ =\ 8\ \ \ OR\ \ x\ =\ -8$

Tags

CCSS.HSA.REI.B.3

CCSS.HSA.REI.A.1

CCSS.HSA.CED.A.1

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#1.4 Solving Absolute Value Equations

Solve for x: ∣x+6∣=11\left|x+6\right|=11∣x+6∣=11

Solve: ∣2x−1∣=−4\left|2x-1\right|=-4∣2x−1∣=−4

Solve for x: ∣3x−6∣−9=−3\left|3x-6\right|-9=-3∣3x−6∣−9=−3

∣x∣=5\left|x\right|=5∣x∣=5 Solve for x:

Solve: ∣x−12∣−3=11\left|x-12\right|-3=11∣x−12∣−3=11

Solve for x: −2∣5x−1∣−3=−11-2\left|5x-1\right|-3=-11−2∣5x−1∣−3=−11

Solve: 4∣2x+7∣=164\left|2x+7\right|=164∣2x+7∣=16

On a soundtrack the minimum length of a song is 3 minutes and the maximum length is 5 minutes. Write an absolute value equation that represents this minimum and maximum.

Solve for x: ∣x+3∣=−2\left|x+3\right|=-2∣x+3∣=−2

Solve for x: ∣−3x∣=15\left|-3x\right|=15∣−3x∣=15

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Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Solve for x:
$\left|x+6\right|=11$

Solve:

$\left|2x-1\right|=-4$

Solve for x:

$\left|3x-6\right|-9=-3$

$\left|x\right|=5$ Solve for x:

Solve:
$\left|x-12\right|-3=11$

Solve for x:

$-2\left|5x-1\right|-3=-11$

Solve:

$4\left|2x+7\right|=16$

Solve for x:

$\left|x+3\right|=-2$

Solve for x:

$\left|-3x\right|=15$