Unit 10 Review

Simplifying using the laws of logarithms

• log(10)

• log(21)

• log(343)

• log(4)

Tags

CCSS.HSA.SSE.B.3

Simplifying using the laws of logarithms

• log(10)

• log(3)

• log(20)

• log(75)

Tags

CCSS.HSA.SSE.B.3

Simplify using the laws of logs

• log(7)

• log(294)

• 1.5log(7)

• 5log(7)

Using the change of base rule, what is this logarithm equivalent to?

• A
• B
• C
• D

Tags

CCSS.HSF.BF.B.5

Write as a single log:
 log 12 + 2 log x

• log (12 + 2x)
• log (14x)
• log (12 * 2x)
• log (12x²)

Rewrite as a single log:
4 log g - 2 log h

• log (4g/2h)
• log (g⁴/h²)
• log (g⁴ - h²)
• log (2gh)

Solve:
_{log (4x − 5) = log (2x − 1)} 

• 0
• 1
• 2
• 3

log₅(4x-7)=log₅(x+5)

• 3
• 12
• 4
• 7

Tags

CCSS.HSF.BF.B.5

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

CCSS.HSF.LE.A.4

log(2x) - log(5) = log(30)

• 6/5
• 45/2
• 75
• -3/8

Tags

CCSS.HSF.BF.B.5

CCSS.HSA.REI.A.1

CCSS.HSA.CED.A.1

log(4x) - log(4) = log(12)

• 12
• 4
• 10
• 100