8 − 3 ( k + 2 ) = 2 − 3 k 8-3\left(k+2\right)=2-3k 8 − 3 ( k + 2 ) = 2 − 3 k

I n f i n i t e S o l u t i o n s Infinite\ Solutions I n f i n i t e S o l u t i o n s

N o S o l u t i o n s No\ Solutions N o S o l u t i o n s

− 7 ( a − 3 ) = 11 − 7 a -7\left(a-3\right)=11-7a − 7 ( a − 3 ) = 1 1 − 7 a

N o S o l u t i o n No\ Solution N o S o l u t i o n

I n f i n i t e S o l u t i o n s Infinite\ Solutions I n f i n i t e S o l u t i o n s

∣ x + 1 ∣ = 6 \left|x+1\right|=6 ∣ x + 1 ∣ = 6

{ − 7 , 5 } \left\{-7,\ 5\right\} { − 7 , 5 }

{ 7 , − 5 } \left\{7,\ -5\right\} { 7 , − 5 }

{ − 7 , 3 } \left\{-7,\ 3\right\} { − 7 , 3 }

{ 7 , 3 } \left\{7,\ 3\right\} { 7 , 3 }

∣ 6 c − 18 ∣ = 30 \left|6c-18\right|=30 ∣ 6 c − 1 8 ∣ = 3 0

{ − 2 , 8 } \left\{-2,\ 8\right\} { − 2 , 8 }

{ − 8 , 2 } \left\{-8,\ 2\right\} { − 8 , 2 }

{ 8 , 2 } \left\{8,\ 2\right\} { 8 , 2 }

{ 2 , − 8 } \left\{2,\ -8\right\} { 2 , − 8 }

− 4 ∣ 2 w + 6 ∣ = − 32 -4\left|2w+6\right|=-32 − 4 ∣ 2 w + 6 ∣ = − 3 2

{ − 7 , 1 } \left\{-7,1\right\} { − 7 , 1 }

{ 7 , − 1 } \left\{7,\ -1\right\} { 7 , − 1 }

{ 1 , − 7 } \left\{1,\ -7\right\} { 1 , − 7 }

{ − 1 , 7 } \left\{-1,\ 7\right\} { − 1 , 7 }

5 ∣ 4 x − 4 ∣ − 9 = 31 5\left|4x-4\right|-9=31 5 ∣ 4 x − 4 ∣ − 9 = 3 1

{ − 1 , 3 } \left\{-1,\ 3\right\} { − 1 , 3 }

{ 1 , − 3 } \left\{1,\ -3\right\} { 1 , − 3 }

{ 3 , − 1 } \left\{3,\ -1\right\} { 3 , − 1 }

{ − 3 , 1 } \left\{-3,\ 1\right\} { − 3 , 1 }

S o l v e : I = p r t f o r t Solve:\ I=prt\ \ \ for\ \ t S o l v e : I = p r t f o r t

t = I p r t=\frac{I}{pr} t = p r I

t = I − p r t=I-pr t = I − p r

t = I p − r t=\frac{I}{p}-r t = p I − r

S o l v e : A x + B y = C f o r y Solve:\ Ax\ +\ By\ =\ C\ for\ y S o l v e : A x + B y = C f o r y

y = C − A x B y=\frac{C-Ax}{B} y = B C − A x

y = C + A x − B y=C+Ax\ -B y = C + A x − B

y = C A x − B y=\frac{C}{Ax}-B y = A x C − B

y = C − A x − B y=\ C-Ax-B y = C − A x − B

S o l v e : r = 4 3 ( p − q ) f o r p Solve:\ r=\frac{4}{3}\left(p-q\right)\ for\ p S o l v e : r = 3 4 ( p − q ) f o r p

p = 3 4 r + q p=\frac{3}{4}r+q p = 4 3 r + q

p = 4 3 r − q p=\frac{4}{3}r-q p = 3 4 r − q

p = 4 3 r + q p=\frac{4}{3}r+q p = 3 4 r + q

p = 4 3 q + r p=\frac{4}{3}q+r p = 3 4 q + r

− 4 x − 11 > 5 o r 8 x − 7 > 9 -4x-11>5\ or\ 8x-7>9 − 4 x − 1 1 > 5 o r 8 x − 7 > 9

x < − 4 o r x > 2 x<-4\ or\ x>2 x < − 4 o r x > 2

x < − 2 o r x > 4 x<-2\ or\ x\ >4 x < − 2 o r x > 4

x < 2 o r x > 4 x<\ 2\ or\ x>\ 4 x < 2 o r x > 4

x < − 1 o r x > 1 x<-1\ or\ x>1 x < − 1 o r x > 1

− 2 x − 1 < − 17 o r 1 − x ≥ 4 -2x-1<-17\ or\ 1-x\ge4 − 2 x − 1 < − 1 7 o r 1 − x ≥ 4

x ≤ − 3 o r x > 8 x\le-3\ or\ x>8 x ≤ − 3 o r x > 8

x < 3 o r x > 8 x<3\ or\ x>8 x < 3 o r x > 8

x < − 3 o r x ≥ 8 x<-3\ or\ x\ge8 x < − 3 o r x ≥ 8

x < − 2 o r x > 5 x<-2\ or\ x>5 x < − 2 o r x > 5

− 31 < 9 x + 5 < 32 -31<9x+5<32 − 3 1 < 9 x + 5 < 3 2

− 4 < x < 3 -4<x<3 − 4 < x < 3

− 3 < x < 4 -3<x<4 − 3 < x < 4

− 4 ≤ x ≤ 3 -4\le x\le3 − 4 ≤ x ≤ 3

− 24 ≤ 2 x − 10 < − 6 -24\le2x-10<-6 − 2 4 ≤ 2 x − 1 0 < − 6

− 7 ≤ x < 2 -7\le x<2 − 7 ≤ x < 2

− 7 < x ≤ 2 -7<x\le2 − 7 < x ≤ 2

− 7 ≤ x ≤ 2 -7\le x\le2 − 7 ≤ x ≤ 2

− 7 < x < 2 -7<x<2 − 7 < x < 2

∣ 2 x + 8 ∣ ≥ 6 \left|2x+8\right|\ge6 ∣ 2 x + 8 ∣ ≥ 6

x ≤ − 7 o r x ≥ 1 x\le-7\ or\ x\ge1 x ≤ − 7 o r x ≥ 1

x < − 7 o r x > 1 x<-7\ or\ x>1 x < − 7 o r x > 1

x ≤ 1 o r x ≥ 7 x\le1\ or\ x\ge7 x ≤ 1 o r x ≥ 7

x < 1 o r x > 7 x<1\ or\ x>7 x < 1 o r x > 7

2 ∣ x − 4 ∣ − 7 ≤ 1 2\left|x-4\right|-7\le1 2 ∣ x − 4 ∣ − 7 ≤ 1

0 ≤ x ≤ 8 0\le x\le8 0 ≤ x ≤ 8

− 2 ≤ x ≤ 6 -2\le x\le6 − 2 ≤ x ≤ 6

− 1 ≤ x < 8 -1\le x<8 − 1 ≤ x < 8

Solving Equations and Inequalities Unit Review

8th - 9th Grade

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25 Qs

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Solving Equations and Inequalities Unit Review

Quiz

•

Mathematics

•

8th - 9th Grade

•

Practice Problem

•

Medium

•

CCSS

HSA.CED.A.4, 8.EE.C.7B, 8.EE.C.7A

Standards-aligned

Amy Hammers

Used 6+ times

FREE Resource

25 questions

Show all answers

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$-5\left(x-2\right)-\left(x+2\right)=50$

$7$

$-7$

$-10$

$5$

Tags

CCSS.8.EE.C.7B

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$8-3\left(k+2\right)=2-3k$

$Infinite\ Solutions$

$7$

$No\ Solutions$

$13$

Tags

CCSS.8.EE.C.7A

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$3w-\left(7w+12\right)=2\left(w-3\right)$

$0$

$-1$

$2$

$1$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$-7\left(a-3\right)=11-7a$

$No\ Solution$

$Infinite\ Solutions$

$0$

$11$

Tags

CCSS.8.EE.C.7A

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$9\left(n-4\right)-7n=32-2\left(n+8\right)$

$15$

$-13$

$8$

$13$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$4\left(4y-3\right)-\left(y-5\right)=-52$

$-2$

$1$

$-3$

$3$

Tags

CCSS.8.EE.C.7B

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$\left|x+1\right|=6$

$\left\{7,\ -5\right\}$

$\left\{-7,\ 5\right\}$

$\left\{-7,\ 3\right\}$

$\left\{7,\ 3\right\}$

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Solving Equations and Inequalities Unit Review

25 questions

$-5\left(x-2\right)-\left(x+2\right)=50$

$8-3\left(k+2\right)=2-3k$

$3w-\left(7w+12\right)=2\left(w-3\right)$

$-7\left(a-3\right)=11-7a$

$9\left(n-4\right)-7n=32-2\left(n+8\right)$

$4\left(4y-3\right)-\left(y-5\right)=-52$

$\left|x+1\right|=6$

$\left|6c-18\right|=30$

$-4\left|2w+6\right|=-32$

$5\left|4x-4\right|-9=31$

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Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Solving Equations and Inequalities Unit Review

25 questions

−5(x−2)−(x+2)=50-5\left(x-2\right)-\left(x+2\right)=50−5(x−2)−(x+2)=50

8−3(k+2)=2−3k8-3\left(k+2\right)=2-3k8−3(k+2)=2−3k

3w−(7w+12)=2(w−3)3w-\left(7w+12\right)=2\left(w-3\right)3w−(7w+12)=2(w−3)

−7(a−3)=11−7a-7\left(a-3\right)=11-7a−7(a−3)=11−7a

9(n−4)−7n=32−2(n+8)9\left(n-4\right)-7n=32-2\left(n+8\right)9(n−4)−7n=32−2(n+8)

4(4y−3)−(y−5)=−524\left(4y-3\right)-\left(y-5\right)=-524(4y−3)−(y−5)=−52

∣x+1∣=6\left|x+1\right|=6∣x+1∣=6

∣6c−18∣=30\left|6c-18\right|=30∣6c−18∣=30

−4∣2w+6∣=−32-4\left|2w+6\right|=-32−4∣2w+6∣=−32

5∣4x−4∣−9=315\left|4x-4\right|-9=315∣4x−4∣−9=31

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$-5\left(x-2\right)-\left(x+2\right)=50$

$8-3\left(k+2\right)=2-3k$

$3w-\left(7w+12\right)=2\left(w-3\right)$

$-7\left(a-3\right)=11-7a$

$9\left(n-4\right)-7n=32-2\left(n+8\right)$

$4\left(4y-3\right)-\left(y-5\right)=-52$

$\left|x+1\right|=6$

$\left|6c-18\right|=30$

$-4\left|2w+6\right|=-32$

$5\left|4x-4\right|-9=31$