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Limit dan Turunan Fungsi Aljabar

Authored by Ani Ismayani

Mathematics

12th Grade

Used 395+ times

Limit dan Turunan Fungsi Aljabar
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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Nilai dari limx2 x25x+6x2\lim_{x\rightarrow2}\ \frac{x^2-5x+6}{x-2}  adalah ...

 14-\frac{1}{4}  

 18-\frac{1}{8}  

 1-1  

 14\frac{1}{4} 

 54\frac{5}{4}  

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 limx2 x25x+6x22=....\lim_{x\rightarrow2}\ \frac{x^2-5x+6}{x^2-2}=....  

 12-\frac{1}{2}  

 14-\frac{1}{4}  

 00  

 14\frac{1}{4}  

 12\frac{1}{2}  

3.

MULTIPLE CHOICE QUESTION

30 sec • 12 pts

Turunan pertama dari  y=2x34x2+2y=2x^3-4x^2+2  adalah ....

 y=6x28x+2y'=6x^2-8x+2  

 y=6x2+8x+2y'=6x^2+8x+2  

 y=6x38x2y'=6x^3-8x^2  

 y=6x28xy'=6x^2-8x  

 y=6x2+8xy'=6x^2+8x  

4.

MULTIPLE CHOICE QUESTION

30 sec • 12 pts

Diketahui  f(x)=2x32x24x+1f\left(x\right)=2x^3-2x^2-4x+1 . Turunan pertama dari  f(x)f\left(x\right)  adalah  f(x)=....f'\left(x\right)=....  

 6x24x46x^2-4x-4  

 2x22x42x^2-2x-4  

 6x24x36x^2-4x-3  

 6x34x246x^3-4x^2-4  

 6x34x24x6x^3-4x^2-4x  

5.

MULTIPLE CHOICE QUESTION

30 sec • 12 pts

 y=(x21)(x3+3)y=\left(x^2-1\right)\left(x^3+3\right)  Turunan pertama dari adalah ....

 x5x3+3x23x^5-x^3+3x^2-3  

 5x4+3x2+6x5x^4+3x^2+6x  

 5x43x2+6x5x^4-3x^2+6x  

 5x43x26x5x^4-3x^2-6x  

 x4x2+xx^4-x^2+x  

6.

MULTIPLE CHOICE QUESTION

30 sec • 12 pts

 Turunan pertama dari f(x)=(2x2+x+1)5f\left(x\right)=\left(2x^2+x+1\right)^5 adalah ....

 (2x2+x+1)4\left(2x^2+x+1\right)^4  

 5x(2x2+x+1)45x\left(2x^2+x+1\right)^4  

 (20x+1)(2x2+x+1)4\left(20x+1\right)\left(2x^2+x+1\right)^4  

 (4x+1)(2x2+x+1)4\left(4x+1\right)\left(2x^2+x+1\right)^4  

 (20x+5)(2x2+x+1)4\left(20x+5\right)\left(2x^2+x+1\right)^4  

7.

MULTIPLE CHOICE QUESTION

30 sec • 12 pts

Turunan dari f(x)=2x14x+3,x34f\left(x\right)=\frac{2x-1}{4x+3},x\ne\frac{3}{4}  adalah ....

 f(x)=10(4x+3)2f'\left(x\right)=\frac{-10}{\left(4x+3\right)^2}  

 f(x)=5(4x+3)2f'\left(x\right)=\frac{-5}{\left(4x+3\right)^2}  

 f(x)=2(4x+3)2f'\left(x\right)=\frac{2}{\left(4x+3\right)^2}  

 f(x)=5(4x+3)2f'\left(x\right)=\frac{5}{\left(4x+3\right)^2}  

 f(x)=10(4x+3)2f'\left(x\right)=\frac{10}{\left(4x+3\right)^2}  

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