Numeros naturales

Authored by Maria Jose Novillo Rodriguez

Mathematics

8th Grade

CCSS covered

Used 680+ times

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10 questions

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MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$5^2\cdot5^7\div5^3=$

$5^6$

$5^0$

$5^{12}$

Tags

CCSS.8.EE.A.1

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\left(10-4\cdot2\right)^2+\sqrt{25}$

Tags

CCSS.7.EE.B.3

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\sqrt{169}$

Tags

CCSS.8.EE.A.2

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\left(7^2\right)^3=$

$7^5$

$7^6$

$7^1$

Tags

CCSS.8.EE.A.1

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\left[\sqrt{64}-\left(2\cdot3+1^2\right)\right]=$

Tags

CCSS.HSN.RN.A.2

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$2^2\cdot4^5=$

$2^7$

$4^7$

$2^{12}$

No se puede resolver

Tags

CCSS.8.EE.A.1

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\sqrt{225}=$

Tags

CCSS.8.EE.A.2

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\left(5\cdot8\right)-\left(3\cdot5\right)=$

Tags

CCSS.7.NS.A.2C

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\left[\left(2\cdot3\right)^2-\sqrt{36}\right]=$

Tags

CCSS.HSN.RN.A.2

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\left[\left(3\cdot2^2\right)-\sqrt{100}\right]=$

Tags

CCSS.HSN.RN.A.2

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Numeros naturales

52⋅57÷53=5^2\cdot5^7\div5^3=52⋅57÷53=

(10−4⋅2)2+25\left(10-4\cdot2\right)^2+\sqrt{25}(10−4⋅2)2+25​

169\sqrt{169}169​

(72)3=\left(7^2\right)^3=(72)3=

[64−(2⋅3+12)]=\left[\sqrt{64}-\left(2\cdot3+1^2\right)\right]=[64​−(2⋅3+12)]=

22⋅45=2^2\cdot4^5=22⋅45=

225=\sqrt{225}=225​=

(5⋅8)−(3⋅5)=\left(5\cdot8\right)-\left(3\cdot5\right)=(5⋅8)−(3⋅5)=

[(2⋅3)2−36]=\left[\left(2\cdot3\right)^2-\sqrt{36}\right]=[(2⋅3)2−36​]=

[(3⋅22)−100]=\left[\left(3\cdot2^2\right)-\sqrt{100}\right]=[(3⋅22)−100​]=

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$5^2\cdot5^7\div5^3=$

$\left(10-4\cdot2\right)^2+\sqrt{25}$

$\sqrt{169}$

$\left(7^2\right)^3=$

$\left[\sqrt{64}-\left(2\cdot3+1^2\right)\right]=$

$2^2\cdot4^5=$

$\sqrt{225}=$

$\left(5\cdot8\right)-\left(3\cdot5\right)=$

$\left[\left(2\cdot3\right)^2-\sqrt{36}\right]=$

$\left[\left(3\cdot2^2\right)-\sqrt{100}\right]=$