Intro to Circles

• (x+1)² + (y +1)² = 3

• (x+1)² + (y -1)² = 3

• (x+1)² + (y +1)² = 9

• (x-1)² + (y -1)² = 9

Write the equation of a circle with center (7, 0) with radius 3. 

• (x - 7)² + y² = 9
• x² + (y -7)² = 9
• (x - 7)² + y² = 3
• x² + (y -7)² = 3

Tags

CCSS.HSG.GPE.A.1

In the equation (x+2)²+(y-3)²=4, the radius of the circle is...

• 4
• 2
• 3
• 16

Tags

CCSS.HSG.GPE.A.1

In the equation (x-3)²+(y-2)²=16, the center of the circle is...

• (3,2)
• (-3, -2)
• (-2, -3)
• (2, 3)

Tags

CCSS.HSG.GPE.A.1

What is the equation for this circle?

• (x+1)+(y+1)=9
• x²+y²=9
• x+y=9

Tags

CCSS.HSG.GPE.A.1

What is the equation of the circle, with center (-6,-9) and radius 7 units?

• (x + 6)^2 + (y + 9)^2 = 49

• (x + 6)^2 + (y + 9)^2 = 7

• (x - 6)^2 + (y - 9)^2 = 49

• (x - 6)^2 + (y - 9)^2 = 7

Tags

CCSS.HSG.GPE.A.1

Write the equation of a circle in standard form that has endpoints of a diameter at (-2,4) and (4,8)

• $\left(x+1\right)^2+\left(y+6\right)^2=52$

• $\left(x-1\right)^2+\left(y-6\right)^2=13$

• $\left(x-1\right)^2+\left(y-6\right)^2=\sqrt{13}$

• $\left(x-1\right)^2+\left(y-6\right)^2=2\sqrt{13}$