Math 2: Quadratic Word Problems

Math 2: Quadratic Word Problems

10th Grade

10 Qs

quiz-placeholder

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Math 2: Quadratic Word Problems

Math 2: Quadratic Word Problems

Assessment

Quiz

10th Grade

Hard

Created by

Mazella Sloan

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A dolphin jumps from the water at at initial velocity of 16 feet per second. The equation h = -8t2 + 16t models the dolphin's height at any given time, t. What is the maximum height the dolphin jumps?

1 foot

5 feet

7 feet

8 feet

12 feet

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A frog is sitting on the ground when he is scared by a big dog. His movement is modeled by the equation h = -6t2 + 6t where h is the frog's height at any given time, t . How many seconds until the frog is back on the ground?

0.5 seconds

1 second

1.5 seconds

2 seconds

3 seconds

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A toy rocket is launched from the top of a 48-foot hill. The rocket's height, h(x), is modeled by the

equation h(x) = -16x2 + 32x +48 after x seconds. How high was the rocket at 2 seconds?

3

32

48

64

100

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

An object in launched directly upward at 64 feet per second (ft/s) from a platform 80 feet high. Its height is represented by the equation

s(t) = –16t2 + 64t + 80

What will be the object's maximum height?

2 ft

80 ft

144 ft

64 ft

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

You jump off a 24 foot high cliff and your fall is modeled by the function:

h(t) = -16t2 + 8t + 24

When would you reach 16 feet above the water?

8 seconds

1 second

1/2 second

1/4 second

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

You jump off a 24 foot high cliff and your fall is modeled by the function:

h(t) = -16t2 + 8t + 24

How long would it take you to hit the water?

8 seconds

1 second

1.5 seconds

1/4 second

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A diver is standing on a platform above the pool. He jumps form the platform with an initial upward velocity of 8 ft/s. Use the formula: h(t) = −16 t2 + 8t + 24

How high is the platform?

.25 ft

24 ft

25 ft

8 ft

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