Algebra 1 Module 1 Lesson 17 EOC Quiz Review

Solve for x:

 $\frac{3\left(x+5\right)}{7}=x-7$  

•  $-\frac{15}{2}$  

• 16

•  $-\frac{5}{2}$  

• -11

 $\frac{3x+5}{8}=10$  

• -1

•  $\frac{40}{3}$  

•  $\frac{13}{3}$  

• 25

$8-2x\ge\frac{-5x+4}{3}$

• $x\le20$

• $x\ge-\frac{7}{3}$

• $x\ge-\frac{4}{3}$

• $x\le12$

 $\frac{6x-5}{3}=2x+4$  

• 17

• -5

• all real numbers

• no solution

$2\left(x-5\right)+4x=6\left(x-1\right)-4$

• 0

• $\frac{5}{3}$

• all real numbers

• no solution

Which equation will have infinite solutions?

• $3x=2x+1$

• $5x=4x$

• $x+1=x$

• $x+5=3+\left(2+x\right)$

Which equation will have no solution?

• $x=x+1$

• $x+5=-5$

• $x+3=3$

• $x+5=x+1+4$