Search Header Logo

College Algebra Final Review

Authored by Deborah Weems

11th Grade - University

CCSS covered

Used 42+ times

College Algebra Final Review
AI

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

    Content View

    Student View

25 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve the equation    3x + 7 = 0

x =  73-\frac{7}{3}  

x =  73\frac{7}{3}  

The solution set is (,)\left(-\infty,\infty\right)  

There is no solution

Tags

CCSS.6.EE.B.7

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve.
 x2 +6x +9 = 14x^2\ +6x\ +9\ =\ 14  

 3±143\pm\sqrt{14}  

 3±14-3\pm\sqrt{14}  

 1111  

 ±14\pm\sqrt{14}  

Tags

CCSS.HSA-REI.B.4B

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find the equation for the circle with center (3,1) and passing through (- 1,4)

(x+1)2+(y 4)2 = 25\left(x+1\right)^2+\left(y\ -\ 4\right)^2\ =\ 25

(x+1)2+(y 4)2 = 5\left(x+1\right)^2+\left(y\ -\ 4\right)^2\ =\ 5

(x3)2+(y 1)2 = 25\left(x-3\right)^2+\left(y\ -\ 1\right)^2\ =\ 25

(x3)2+(y 1)2 = 5\left(x-3\right)^2+\left(y\ -\ 1\right)^2\ =\ 5

Tags

CCSS.HSG.GPE.A.1

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

For the pair of functions, find the indicated sum, difference, product, or quotient.

f(x) = 8x - 7, g(x) = 5x - 3

Find ( f- g)(x)

3x - 4

-3x + 4

3x - 10

13x - 10

Tags

CCSS.HSF-BF.A.1B

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find the domain of the function. 
 f(x)=8x2f\left(x\right)=\frac{8}{x^2}  

 ({xx>8},or(8,)\left(\left\{x|x>8\right\},or(8,\infty\right)  

 ({xx<2},or (,2)\left(\left\{x|x<2\right\},or\ (-\infty,2\right)  

 ({xx0},or (,0)U(0,)\left(\left\{x|x\ne0\right\},or\ (-\infty,0\right)U\left(0,\infty\right)  

All real numbers  (,)\left(-\infty,\infty\right)  

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Use the quadratic formula to find the exact solutions.
 x2  10x + 61 = 0x^2\ -\ 10x\ +\ 61\ =\ 0  

 5±6i5\pm6i  

 11, 111,\ -1  

 5 ± 6i-5\ \pm\ 6i  

 10 ±12i10\ \pm12i  

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find an equation fro the circle.
Center at  (2,8)\left(2,-8\right) , radius of length  12\frac{1}{2}  

 (x  2)2 + (y 8)2 = 12\left(x\ -\ 2\right)^2\ +\ \left(y\ -8\right)^2\ =\ \frac{1}{2}  

 (x  2)2 + (y +8)2 = 12\left(x\ -\ 2\right)^2\ +\ \left(y\ +8\right)^2\ =\ \frac{1}{2}  

 (x  2)2 + (y+ 8)2 = 14\left(x\ -\ 2\right)^2\ +\ \left(y+\ 8\right)^2\ =\ \frac{1}{4}  

 (x + 2)2 + (y 8)2 = 14\left(x\ +\ 2\right)^2\ +\ \left(y-\ 8\right)^2\ =\ \frac{1}{4}  

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

Already have an account?