College Algebra Final Review

College Algebra Final Review

11th Grade - University

25 Qs

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Assessment

Quiz

11th Grade - University

Practice Problem

Medium

CCSS
HSA-REI.B.4B, HSF-BF.A.1B, 6.EE.B.7

+12

Standards-aligned

Created by

Deborah Weems

Used 42+ times

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25 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve the equation    3x + 7 = 0

x =  73-\frac{7}{3}  

x =  73\frac{7}{3}  

The solution set is (,)\left(-\infty,\infty\right)  

There is no solution

Tags

CCSS.6.EE.B.7

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve.
 x2 +6x +9 = 14x^2\ +6x\ +9\ =\ 14  

 3±143\pm\sqrt{14}  

 3±14-3\pm\sqrt{14}  

 1111  

 ±14\pm\sqrt{14}  

Tags

CCSS.HSA-REI.B.4B

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find the equation for the circle with center (3,1) and passing through (- 1,4)

(x+1)2+(y 4)2 = 25\left(x+1\right)^2+\left(y\ -\ 4\right)^2\ =\ 25

(x+1)2+(y 4)2 = 5\left(x+1\right)^2+\left(y\ -\ 4\right)^2\ =\ 5

(x3)2+(y 1)2 = 25\left(x-3\right)^2+\left(y\ -\ 1\right)^2\ =\ 25

(x3)2+(y 1)2 = 5\left(x-3\right)^2+\left(y\ -\ 1\right)^2\ =\ 5

Tags

CCSS.HSG.GPE.A.1

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

For the pair of functions, find the indicated sum, difference, product, or quotient.

f(x) = 8x - 7, g(x) = 5x - 3

Find ( f- g)(x)

3x - 4

-3x + 4

3x - 10

13x - 10

Tags

CCSS.HSF-BF.A.1B

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find the domain of the function. 
 f(x)=8x2f\left(x\right)=\frac{8}{x^2}  

 ({xx>8},or(8,)\left(\left\{x|x>8\right\},or(8,\infty\right)  

 ({xx<2},or (,2)\left(\left\{x|x<2\right\},or\ (-\infty,2\right)  

 ({xx0},or (,0)U(0,)\left(\left\{x|x\ne0\right\},or\ (-\infty,0\right)U\left(0,\infty\right)  

All real numbers  (,)\left(-\infty,\infty\right)  

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Use the quadratic formula to find the exact solutions.
 x2  10x + 61 = 0x^2\ -\ 10x\ +\ 61\ =\ 0  

 5±6i5\pm6i  

 11, 111,\ -1  

 5 ± 6i-5\ \pm\ 6i  

 10 ±12i10\ \pm12i  

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find an equation fro the circle.
Center at  (2,8)\left(2,-8\right) , radius of length  12\frac{1}{2}  

 (x  2)2 + (y 8)2 = 12\left(x\ -\ 2\right)^2\ +\ \left(y\ -8\right)^2\ =\ \frac{1}{2}  

 (x  2)2 + (y +8)2 = 12\left(x\ -\ 2\right)^2\ +\ \left(y\ +8\right)^2\ =\ \frac{1}{2}  

 (x  2)2 + (y+ 8)2 = 14\left(x\ -\ 2\right)^2\ +\ \left(y+\ 8\right)^2\ =\ \frac{1}{4}  

 (x + 2)2 + (y 8)2 = 14\left(x\ +\ 2\right)^2\ +\ \left(y-\ 8\right)^2\ =\ \frac{1}{4}  

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