Bentuk sederhana dari 2 + 3 5 2 − 5 \frac{\sqrt{2}+3\sqrt{5}}{\sqrt{2}-\sqrt{5}} 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> + 3 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> adalah ...

− 1 3 ( 17 + 4 10 ) \frac{-1}{3}\left(17+4\sqrt{10}\right) 3 − 1 ( 1 7 + 4 1 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

1 3 ( 17 − 4 10 ) \frac{1}{3}\left(17-4\sqrt{10}\right) 3 1 ( 1 7 − 4 1 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

− 2 3 ( 15 + 4 10 ) \frac{-2}{3}\left(15+4\sqrt{10}\right) 3 − 2 ( 1 5 + 4 1 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

2 3 ( 15 − 4 10 ) \frac{2}{3}\left(15-4\sqrt{10}\right) 3 2 ( 1 5 − 4 1 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

− 1 3 ( 17 − 4 10 ) \frac{-1}{3}\left(17-4\sqrt{10}\right) 3 − 1 ( 1 7 − 4 1 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

B e n t u k s e d e r h a n a d a r i 5 − 2 5 + 3 2 a d a l a h . . . . Bentuk\ sederhana\ dari\ \frac{\sqrt{5}-\sqrt{2}}{\sqrt{5}+3\sqrt{2}}\ adalah.... B e n t u k s e d e r h a n a d a r i 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> + 3 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> a d a l a h . . . .

1 13 ( − 11 + 4 10 ) \frac{1}{13}\left(-11+4\sqrt{10}\right) 1 3 1 ( − 1 1 + 4 1 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

− 1 13 ( − 11 + 4 10 ) \frac{-1}{13}\left(-11+4\sqrt{10}\right) 1 3 − 1 ( − 1 1 + 4 1 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

− 11 13 ( − 1 + 4 10 ) \frac{-11}{13}\left(-1+4\sqrt{10}\right) 1 3 − 1 1 ( − 1 + 4 1 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

1 13 ( 11 − 4 10 ) \frac{1}{13}\left(11-4\sqrt{10}\right) 1 3 1 ( 1 1 − 4 1 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

− 1 13 ( 11 + 4 10 ) \frac{-1}{13}\left(11+4\sqrt{10}\right) 1 3 − 1 ( 1 1 + 4 1 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

Diketahui 2 log 3 = x dan 2 log 10 = y. Nilai 6 log 120 = ....

x + y + 2 x + 1 \frac{x+y+2}{x+1} x + 1 x + y + 2

x + 1 x + y + 2 \frac{x+1}{x+y+2} x + y + 2 x + 1

x x y + 2 \frac{x}{xy+2} x y + 2 x

x y + 2 x \frac{xy+2}{x} x x y + 2

2 x y x + 1 \frac{2xy}{x+1} x + 1 2 x y

Himpunan penyelesaian dari persamaan kuadrat 2 x 2 – 3 x – 14 = 0 adalah ...

{ − 2 , 7 2 } \left\{-2,\frac{7}{2}\right\} { − 2 , 2 7 }

{ 2 , 3 2 } \left\{2,\frac{3}{2}\right\} { 2 , 2 3 }

{ − 3 2 , 2 } \left\{\frac{-3}{2},2\right\} { 2 − 3 , 2 }

Himpunan penyelesaian dari persamaan: 5 x 2 + 4 x – 12 = 0 adalah ... .

{ − 2 , 6 5 } \left\{-2,\frac{6}{5}\right\} { − 2 , 5 6 }

{ − 2 , 5 6 } \left\{-2,\frac{5}{6}\right\} { − 2 , 6 5 }

{ 2 , − 5 6 } \left\{2,\frac{-5}{6}\right\} { 2 , 6 − 5 }

{ 2 , 6 5 } \left\{2,\frac{6}{5}\right\} { 2 , 5 6 }

{ − 2 , − 6 5 } \left\{-2,\frac{-6}{5}\right\} { − 2 , 5 − 6 }

Seorang penjaja buah-buahan menggunakan gerobak, menjual salak dan rambutan. Harga pembelian salak Rp 2.500 per kg dan rambutan Rp 2.000 per kg. Modal yang tersedia Rp 800.000, sedangkan muatan gerobag tidak lebih dari 4 kuintal. Model matematika persoalan tersebut adalah …

5x + 4y ≤ 1.600, x + y ≤400, x≥0, y≥ 0

5x + 4y ≥ 1.600, x + y ≤400, x≥0, y≥ 0

5x + 4y ≤ 1.600, x + y ≥400, x≥0, y≥ 0

5x + 4y ≤ 1.600, x + y <400, x≥0, y≥ 0

5x + 4y < 1.600, x + y <400, x≥0, y≥ 0

Seorang penjual majalah akan membeli paling banyak 40 majalah yang terdiri dari jenis A seharga Rp 20.000,00 per eksemplar dan jenis B dengan harga Rp 35.000,00 per eksemplar. Jumlah uang yang dimiliki hanya Rp 920.000,00. Maka model matematika yang sesuai adalah ….

x+y ≤ 40, 20x+35y ≤ 920, x ≥ 0, y ≥ 0

x-y ≤ 40, 20x-35y ≤ 920, x ≥ 0, y ≥ 0

x+y ≥ 40, 20x+35y ≥ 920, x ≥ 0, y ≥ 0

x+y = 40, 20x+35y = 920, x ≥ 0, y ≥ 0

Untuk membuat sebuah pagar diperlukan besi panjang 20 batang dan besi pendek 15 batang, sedangkan untuk membuat teralis jendela diperlukan besi panjang setengahnya dari yang digunakan untuk membuat pagar dan besi pendek dua kali lipatnya. Tersedia 70 batang besi panjang dan 45 batang besi pendek maka model matematika yang sesuai untuk soal cerita diatas adalah … .

20x+10y≤70, 15x+30y≤45, x≥0, y≥ 0

20x+15y≤70, 10x+30 ≤45, x≥0, y≥ 0

20x+15y ≤70, 40x+7,5y≤45, x≥0, y≥0

20x+40y≤70, 15x+7,5y≤45, x>≥0, y≥ 0

20x+40y≤70, 15x+30y≤45, x≥0, y≥0

SLAMET DADARAN sepuluh GANJIL TAUN RONG EWU SANGALAS

Authored by Agus Muslim

Mathematics

10th Grade

Used 9+ times

SLAMET DADARAN sepuluh GANJIL TAUN RONG EWU SANGALAS

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40 questions

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MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Diketahui a = 4, b = 2 dan c =1/2 . Nilai $\left(a^{-1}\right)^2.\ \frac{b^4}{c^{-3}}$ adalah .....

$\frac{1}{2}$

$\frac{1}{4}$

$\frac{1}{8}$

$\frac{1}{16}$

$\frac{1}{32}$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Bentuk sederhana dari $\frac{\sqrt{2}+3\sqrt{5}}{\sqrt{2}-\sqrt{5}}$ adalah ...

$\frac{1}{3}\left(17-4\sqrt{10}\right)$

$\frac{-2}{3}\left(15+4\sqrt{10}\right)$

$\frac{2}{3}\left(15-4\sqrt{10}\right)$

$\frac{-1}{3}\left(17-4\sqrt{10}\right)$

$\frac{-1}{3}\left(17+4\sqrt{10}\right)$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Diketahui ²log 3 = p. Nilai ⁹log 16 adalah ....

$\frac{2}{p}$

$\frac{p}{2}$

$\frac{3}{p}$

$\frac{p}{3}$

$\frac{3p}{4}$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$Nilai\ dari\ \ \frac{a^2b^3c^{-1}}{a^{-2}bc^2}$ , untuk a = 2, b = 3 dan c = 5 adalah ...

$\frac{81}{125}$

$\frac{144}{125}$

$\frac{432}{125}$

$\frac{1296}{125}$

$\frac{2596}{125}$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$Bentuk\ sederhana\ dari\ \frac{\sqrt{5}-\sqrt{2}}{\sqrt{5}+3\sqrt{2}}\ adalah....$

$\frac{-1}{13}\left(-11+4\sqrt{10}\right)$

$\frac{-11}{13}\left(-1+4\sqrt{10}\right)$

$\frac{1}{13}\left(11-4\sqrt{10}\right)$

$\frac{-1}{13}\left(11+4\sqrt{10}\right)$

$\frac{1}{13}\left(-11+4\sqrt{10}\right)$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Diketahui ²log 3 = x dan ²log 10 = y. Nilai ⁶log 120 = ....

$\frac{x+y+2}{x+1}$

$\frac{x+1}{x+y+2}$

$\frac{x}{xy+2}$

$\frac{xy+2}{x}$

$\frac{2xy}{x+1}$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$Bentuk\ sederhana\ dari\ \left(\frac{3^{-1}a^3b^{-4}}{2a^{-2}b^1}\right)^{^{-1}}\ adalah....$

$\frac{2a^5}{2b^5}$

$\frac{3a^5}{2b^5}$

$\frac{a^5}{6b^5}$

$\frac{6a^5}{b^5}$

$\frac{6b^5}{a^5}$

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SLAMET DADARAN sepuluh GANJIL TAUN RONG EWU SANGALAS

Diketahui a = 4, b = 2 dan c =1/2 . Nilai $\left(a^{-1}\right)^2.\ \frac{b^4}{c^{-3}}$ adalah .....

Bentuk sederhana dari $\frac{\sqrt{2}+3\sqrt{5}}{\sqrt{2}-\sqrt{5}}$ adalah ...

Diketahui ²log 3 = p. Nilai ⁹log 16 adalah ....

$Nilai\ dari\ \ \frac{a^2b^3c^{-1}}{a^{-2}bc^2}$ , untuk a = 2, b = 3 dan c = 5 adalah ...

$Bentuk\ sederhana\ dari\ \frac{\sqrt{5}-\sqrt{2}}{\sqrt{5}+3\sqrt{2}}\ adalah....$

Diketahui ²log 3 = x dan ²log 10 = y. Nilai ⁶log 120 = ....

$Bentuk\ sederhana\ dari\ \left(\frac{3^{-1}a^3b^{-4}}{2a^{-2}b^1}\right)^{^{-1}}\ adalah....$

Pada suatu hari Pak Ahmad, Pak Badrun, dan Pak Yadi panen jeruk. Hasil kebun Pak Yadi lebih sedikit 15 kg dari hasil kebun Pak Ahmad dan lebih banyak 15 kg dari hasil kebun Pak Badrun. Jika jumlah hasil panen ketiga kebun itu 225 kg, maka hasil panen Pak Ahmad adalah …

Harga 2 kg mangga, 2 kg jeruk, dan 1 kg anggur adalah Rp70.000,00 dan harga 1 kg mangga, 2 kg jeruk, dan 2 kg anggur adalah Rp90.000,00. Jika harga 2 kg mangga, 2 kg jeruk, dan 3 kg anggur Rp130.000,00, maka harga 1 kg jeruk adalah …

Himpunan penyelesaian dari sistem persamaan 3x + 4y = l7 dan 5x + 7y = 29 . Adalah

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

SLAMET DADARAN sepuluh GANJIL TAUN RONG EWU SANGALAS

Diketahui a = 4, b = 2 dan c =1/2 . Nilai (a−1)2. b4c−3\left(a^{-1}\right)^2.\ \frac{b^4}{c^{-3}}(a−1)2. c−3b4​ adalah .....

Bentuk sederhana dari 2+352−5\frac{\sqrt{2}+3\sqrt{5}}{\sqrt{2}-\sqrt{5}}2​−5​2​+35​​ adalah ...

Diketahui 2log 3 = p. Nilai 9log 16 adalah ....

Nilai dari a2b3c−1a−2bc2Nilai\ dari\ \ \frac{a^2b^3c^{-1}}{a^{-2}bc^2}Nilai dari a−2bc2a2b3c−1​ , untuk a = 2, b = 3 dan c = 5 adalah ...

Bentuk sederhana dari 5−25+32 adalah....Bentuk\ sederhana\ dari\ \frac{\sqrt{5}-\sqrt{2}}{\sqrt{5}+3\sqrt{2}}\ adalah....Bentuk sederhana dari 5​+32​5​−2​​ adalah....

Diketahui 2log 3 = x dan 2log 10 = y. Nilai 6log 120 = ....

Bentuk sederhana dari (3−1a3b−42a−2b1)−1 adalah....Bentuk\ sederhana\ dari\ \left(\frac{3^{-1}a^3b^{-4}}{2a^{-2}b^1}\right)^{^{-1}}\ adalah....Bentuk sederhana dari (2a−2b13−1a3b−4​)−1 adalah....

Pada suatu hari Pak Ahmad, Pak Badrun, dan Pak Yadi panen jeruk. Hasil kebun Pak Yadi lebih sedikit 15 kg dari hasil kebun Pak Ahmad dan lebih banyak 15 kg dari hasil kebun Pak Badrun. Jika jumlah hasil panen ketiga kebun itu 225 kg, maka hasil panen Pak Ahmad adalah …

Harga 2 kg mangga, 2 kg jeruk, dan 1 kg anggur adalah Rp70.000,00 dan harga 1 kg mangga, 2 kg jeruk, dan 2 kg anggur adalah Rp90.000,00. Jika harga 2 kg mangga, 2 kg jeruk, dan 3 kg anggur Rp130.000,00, maka harga 1 kg jeruk adalah …

Himpunan penyelesaian dari sistem persamaan 3x + 4y = l7 dan 5x + 7y = 29 . Adalah

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Diketahui a = 4, b = 2 dan c =1/2 . Nilai $\left(a^{-1}\right)^2.\ \frac{b^4}{c^{-3}}$ adalah .....

Bentuk sederhana dari $\frac{\sqrt{2}+3\sqrt{5}}{\sqrt{2}-\sqrt{5}}$ adalah ...

Diketahui ²log 3 = p. Nilai ⁹log 16 adalah ....

$Nilai\ dari\ \ \frac{a^2b^3c^{-1}}{a^{-2}bc^2}$ , untuk a = 2, b = 3 dan c = 5 adalah ...

$Bentuk\ sederhana\ dari\ \frac{\sqrt{5}-\sqrt{2}}{\sqrt{5}+3\sqrt{2}}\ adalah....$

Diketahui ²log 3 = x dan ²log 10 = y. Nilai ⁶log 120 = ....

$Bentuk\ sederhana\ dari\ \left(\frac{3^{-1}a^3b^{-4}}{2a^{-2}b^1}\right)^{^{-1}}\ adalah....$