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Równania trygonometryczne

Mathematics

11th Grade

Used 103+ times

Równania trygonometryczne
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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 cosx=32\cos x=\frac{\sqrt{3}}{2}  

 x=π3+2kπ  x=π3+2kπx=-\frac{\pi}{3}+2k\pi\ \vee\ x=\frac{\pi}{3}+2k\pi  

 x=π6+2kπ  x=π6+2kπx=-\frac{\pi}{6}+2k\pi\ \vee\ x=\frac{\pi}{6}+2k\pi  

 x=π4+2kπ  x=π4+2kπx=\frac{\pi}{4}+2k\pi\ \vee\ x=-\frac{\pi}{4}+2k\pi  

 x=2π3+2kπ  x=π3+2kπx=\frac{2\pi}{3}+2k\pi\ \vee\ x=-\frac{\pi}{3}+2k\pi  

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 sinx=12\sin x=\frac{1}{2}  

d x=π4+2kπ  x=3π4+2kπx=-\frac{\pi}{4}+2k\pi\ \vee\ x=\frac{3\pi}{4}+2k\pi  

 x=π3+2kπ  x=2π3+2kπx=\frac{\pi}{3}+2k\pi\ \vee\ x=\frac{2\pi}{3}+2k\pi  

 x=π6+2kπ  x=56π+2kπx=\frac{\pi}{6}+2k\pi\ \vee\ x=\frac{5}{6}\pi+2k\pi  

 x=π3+2kπ  x=π3+2kπx=-\frac{\pi}{3}+2k\pi\ \vee\ x=\frac{\pi}{3}+2k\pi  

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 sin(x)=22\sin\left(x\right)=-\frac{\sqrt{2}}{2}  

 x=π4+2kπ  x=π4+2kπx=-\frac{\pi}{4}+2k\pi\ \vee\ x=\frac{\pi}{4}+2k\pi  

 x=π4+2kπ  x=3π4+2kπx=-\frac{\pi}{4}+2k\pi\ \vee\ x=\frac{3\pi}{4}+2k\pi  

 x=π4+2kπ  x=5π4+2kπx=-\frac{\pi}{4}+2k\pi\ \vee\ x=\frac{5\pi}{4}+2k\pi  

 x=π3+2kπ  x=π3+2kπx=-\frac{\pi}{3}+2k\pi\ \vee\ x=\frac{\pi}{3}+2k\pi  

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 cosx=32\cos x=-\frac{\sqrt{3}}{2}  

 x=π3+2kπ  x=π3+2kπx=-\frac{\pi}{3}+2k\pi\ \vee\ x=\frac{\pi}{3}+2k\pi  

 x=π4+2kπ  x=5π4+2kπx=-\frac{\pi}{4}+2k\pi\ \vee\ x=\frac{5\pi}{4}+2k\pi  

 x=5π6+2kπ  x=7π6+2kπx=\frac{5\pi}{6}+2k\pi\ \vee\ x=\frac{7\pi}{6}+2k\pi  

 x=2π3+2kπ  x=4π3+2kπx=-\frac{2\pi}{3}+2k\pi\ \vee\ x=\frac{4\pi}{3}+2k\pi  

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 sinx=1\sin x=1  

 x=2kπ x=2k\pi\   

 x=π2k x=\frac{\pi}{2}k\   

 x=kπx=k\pi  

 x=π2+2kπ x=\frac{\pi}{2}+2k\pi\   

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 cosx=1\cos x=-1  

 x=π2+kπ x=\frac{\pi}{2}+k\pi\   

 x=π+2kπ x=\pi+2k\pi\   

 x=π2+2kπ x=-\frac{\pi}{2}+2k\pi\   

 x=kπ x=k\pi\   

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 tgx=3tgx=\sqrt{3}  

 x=π3+kπ x=\frac{\pi}{3}+k\pi\   

 x=π6+kπ x=\frac{\pi}{6}+k\pi\   

 x=π2+kπ x=\frac{\pi}{2}+k\pi\   

 x=π3+kπ x=-\frac{\pi}{3}+k\pi\   

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