A2-Mod 7 Finding Rational/Complex solutions of Polynomials

Find all the real zeros of the function 
f(x) = 2x³ - 19x² + 38x + 24 given that x-4 is a factor.

• x = 1/2, -6
• x = -1/2, 6
• x = 4, -1/2, 6
• x = -4, 1/2, -6

Tags

CCSS.HSA.APR.B.2

What are the zeros of the function?

• 4,1
• 3,1,-2,-5
• -3, -1, 2, 5
• -2,4

Tags

CCSS.HSF-IF.C.7C

Factor:
 x³-12x²+47x-60=0 when 5 is a root.

• (x-3)(x-4)(x-5)=0
• (x+1)(x-4)(x-5)=0
• (x-3)(x-4)(2x-5)=0
• (x-5)(x-4)(x-5)=0

Tags

CCSS.HSA.APR.B.2

Find the roots of 0=x³-4x²+2x-8

• ±2,4
• ±2i,4
• ±i√2,4
• ±√2,4

Tags

CCSS.HSA.APR.B.3

Find all the real-number roots for the function below. Use any method you like.

f(x)=6x³−17x²+11x−2

• x = ½, ⅓, 2

• x = ¾, ½, 1

• x = ⅙, ⅚, 2

• x = 1, 2, 3

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.B.3

CCSS.HSA.REI.D.11

Find a polynomial function of degree 3 that has zeroes at
x=1, 2, and 3

• x³ - 6x² + 11x - 6
• x³ - 11x² - 6x - 6
• x³ - 6x² - 6x - 6
• x³ - 11x² - 11x - 11

Find all the real-number roots for the function below. Use any method you like.

f(x)=18x⁴+3x³−17x²+17x−55

• x = 1, -5/2, 2 +- √7 / 3

• x = 1, -3/2, 3 +- √5 / 2

• x = 1, -1/2, 4 +- √3 / 5

• x = 2, -5/2, 5 +- √7 / 4

Find a polynomial function that has zeroes at
x=1+√2, 1-√2, and 1

• x³ - 3x² + x +1
• x³ - 3x² + 3x +1
• x³ - x² + x +3
• x³ - 3x² + 3x +3

Given one complex zero use the conjugate root theorem to find another.  Zero is 7-5i

• -7+5i
• 7-5i
• -7-5i
• 7+5i

Tags

CCSS.HSN.CN.A.3

Given one complex zero use the conjugate root theorem to find another.  Zero is: -12-8i

• 12+8i
• -12+8i
• 12-8i
• -12-8i

Tags

CCSS.HSN.CN.A.3