I can use formal proofs to show triangle congruence

If DA bisects IE, then

• ID=ED
• IA=EA
• <IDA=<EDA
• <IAD and <EAD are right angles

Tags

CCSS.HSG.CO.B.7

CCSS.HSG.CO.B.8

CCSS.HSG.CO.C.10

CCSS.HSG.CO.C.9

CCSS.HSG.SRT.B.5

If DA is perpendicular to IE, then we can immediately conclude that

• IA=AE
• <IAD = <DAE
• <IDA=<EDA
• <IAD and <DAE are right angles

Tags

CCSS.HSG.CO.A.1

CCSS.HSG.CO.C.10

CCSS.HSG.CO.C.9

An angle bisector cuts an angle into two congruent _________

• Angles!
• Segments
• Mysteries

Tags

CCSS.HSG.CO.D.12

Identify the  missing statement or reason

• Given
• Vertical Angles Theorem
• Definition of Angle Bisector
• Alternate Interior Angles Theorem

Tags

CCSS.HSG.SRT.B.5

Identify the missing statement or reason

• Reflexive Property

• Definition of Midpoint

• Given

• Vertical Angles Theorem

Tags

CCSS.HSG.CO.B.7

CCSS.HSG.CO.B.8

CCSS.HSG.CO.C.10

CCSS.HSG.SRT.B.4

CCSS.HSG.SRT.B.5

Identify the  missing statement or reason

• Definition of Angle Bisector
• Alternate Interior Angles Theorem
• Reflexive Property
• Definition of Midpoint

Tags

CCSS.HSG.SRT.B.5

What is the "statement" for step 3 of the proof? 

• ∡EDA≅∡DCB
• ∡AED≅∡BEC
• DE=CE
• ∡AED≅∡CED

Tags

CCSS.HSG.SRT.B.5

• A
• B
• C
• D

Tags

CCSS.HSG.SRT.B.5

• A
• B
• C
• D

Tags

CCSS.HSG.SRT.B.5

• A
• B
• C
• D

Tags

CCSS.HSG.CO.B.6

CCSS.HSG.CO.B.7

CCSS.HSG.CO.B.8

CCSS.HSG.CO.C.10

CCSS.HSG.SRT.B.4

CCSS.HSG.SRT.B.5