Which of the species strong oxidizing agent?
Cl2(g) + 2e → 2Cl-(aq) Eocell = + 1.36 V
Cu2+(aq) + 2e → Cu(s) Eocell = + 0.34 V
Ni2+(aq) + 2e → Ni(s) Eocell = – 0.25 V
Ca2+(aq) + 2e → Ca(s) Eocell = – 2.87 V
SK025 CHAPTER 3:ELECTROCHEMISTRY (GALVANIC CELL)
Quiz
•
Chemistry
•
University
•
Hard
ZUHAIZI ABDULLAH
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15 questions
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1.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Which of the species strong oxidizing agent?
Cl2(g) + 2e → 2Cl-(aq) Eocell = + 1.36 V
Cu2+(aq) + 2e → Cu(s) Eocell = + 0.34 V
Ni2+(aq) + 2e → Ni(s) Eocell = – 0.25 V
Ca2+(aq) + 2e → Ca(s) Eocell = – 2.87 V
Cl2(g)
Cu2+(aq)
Ni2+(aq)
Ca2+(aq)
2.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Which is correct to write cell notation
Anode: Zn
Cathode: Ni
Zn2+ (aq,1M) / Zn (s) // Ni (s) / Ni2+ (aq,1M)
Zn (s) /Zn2+ (aq,1M) // Ni2+ (aq,1M) / Ni (s)
Zn2+ (s,1M) / Zn (aq) // Ni (aq) / Ni2+ (s,1M)
Zn (aq) /Zn2+ (s,1M) // Ni2+ (s,1M) / Ni (aq)
3.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Calculate standard cell potential for this equation:
Zn2+(aq) + 2e → Zn(s) Eº = – 0.76 V
Cd2+(aq) + 2e → Cd(s) Eº = – 0.40 V
Eocell = -0.36 V
Eocell = -1.16 V
Eocell = +1.16 V
Eocell = +0.36 V
4.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Based on cell notation below, give the one electrolyte can be used in cathode?
Zn (s) /Zn2+ (aq,1M) // H+ (aq,1M) / H2 (g,1 atm)/graphite (s)
ZnSO4(aq)
H2(aq)
ZnCl2(aq)
HCl(aq)
5.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Based on the cell notation below, give the suitable X can be used ?
X / H2(g,1 atm)/ H+ (aq,1M) // Ag+ (aq,1M) //Ag (s)
Ag (s)
H (s)
Pt (s)
Zn (s)
6.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Which of the pairs give the highest value of voltage cell?
Al3+(aq) + 3e → Al(s) Eocell = - 1.66 V
Cu2+(aq) + 2e → Cu(s) Eocell = + 0.34 V
Ni2+(aq) + 2e → Ni(s) Eocell = – 0.25 V
Br2(l) + 2e → 2Br-(aq) Eocell = + 1.07 V
Al and Ni
Cu and Br2
Al and Br2
Cu and Ni
7.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Arrange the species increasing order oxidizing agent?
Cl2(g) + 2e → 2Cl-(aq) Eocell = + 1.36 V
Cu2+(aq) + 2e → Cu(s) Eocell = + 0.34 V
Ni2+(aq) + 2e → Ni(s) Eocell = – 0.25 V
Ca2+(aq) + 2e → Ca(s) Eocell = – 2.87 V
Ca < Ni < Cu < Cl-
Cl- < Cu < Ni < Ca
Ca2+ < Ni2+ < Cu2+ < Cl2
Cl2 < Cu2+ < Ni2+ < Ca2+
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