Convert from Vertex to Standard

Which of the following shows
f(x) = x² + 12x - 2
written in vertex form?

• f(x) = (x + 6)² + 142
• f(x) = (x + 6)² - 34
• f(x) = (x + 6)² - 38
• f(x) = (x + 6)² + 34

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

CCSS.HSF.IF.C.8

Convert f(x) = 4x² - 32x + 2 to vertex form.

• f(x) = 4(x + 4)² - 62

• f(x) = 4(x - 4)² - 62

• f(x) = 4(x - 8)² - 62

• f(x) = 4(x + 8)² - 62

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

CCSS.HSF.IF.C.8

Convert f(x) = 3x²+ 6x - 5 to vertex form.

• f(x) = 3(x + 1)² - 8

• f(x) = 3(x - 1) ² - 8

• f(x) = 3(x + 2)² - 8

• f(x) = 3(x - 2)² - 8

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

CCSS.HSF.IF.C.8

Convert to vertex form.

• $y=-2(x+12)^2+77$

• $y=-2(x-12)^2+77$

• $y=-2(x-6)^2+77$

• $y=-2(x+6)^2+77$

Convert to vertex form.

• $y=-\left(x-5\right)^2+21$

• $y=-(x+5)^2+21$

• $y=-(x+10)^2+21$

• $y=-(x-10)^2+21$

Convert to vertex form.

• $y=\frac{1}{3}(x+3)^2-29$

• $y=\frac{1}{3}(x-3)^2-29$

• $y=\frac{1}{3}(x-9)^2-29$

• $y=\frac{1}{3}(x+9)^2-29$

Convert to vertex form.

• $y=\frac{1}{2}(x-4)^2-29$

• $y=\frac{1}{2}(x+4)^2-29$

• $y=\frac{1}{2}(x+8)^2-29$

• $y=\frac{1}{2}(x-8)^2-29$

Find the vertex of 
f(x) = -x² - 4x + 12

• (-2, 16)
• (2, 0)
• (2, 4)
• (-2, 4)

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

CCSS.HSF.IF.C.8

When $2x^2-20x+49=19$   is written in the form  $\left(x-p\right)^2=q$   , what is the value of  $q$  ?

• 19

• 10

• 5

• -30

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Find the zeros of  $f\left(x\right)=x^2+7x+9$  .

•  $x=-7\pm\sqrt{13}$  

•  $x=\frac{-7\pm\sqrt{13}}{2}$  

•  $x=\frac{3\pm\sqrt{7}}{2}$  

•  $x=3\pm\sqrt{7}$  

Tags

CCSS.HSA.REI.B.4