solving systems by substitution

Solve this system of equations. 
y = 2x + 1
y = 4x - 1

• (1,3)
• (-1,-3)
• (-1,3)
• (3,1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• (3,-1)
• (-3,-1)
• (1,2)
• (-1,2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

y = 5x + 1
y = 3x + 13

• (6, 31)
• (31, 6)
• (4, 21)
• (2, 11)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

y = -2x + 5
y = 2x - 11

• No Solution
• (0, 0)
• (3, -1)
• (4, -3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve for x and y
y = 2x + 1
y = 4x - 1

• (1,3)
• (-1,-3)
• (-1,3)
• (3,1)

Tags

CCSS.HSA.REI.C.9

What is the solution to this system of equations?

• (4, -1)
• (-1, 4)
• (-4, 1)
• (-4, -1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

y = -6x + 5
-2x + y = 5

• (-3, -6)
• (-6, 3)
• (0, 5)
• (-3, 5)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

y = -3x + 11
y = -6x - 13

• (-8, 35)
• (8, -13)
• (1, 8)
• (2, 13)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the following system:

 $y=6x-11$  

 $-2x-3y=-7$  

•  $\left(2,\ 1\right)$  

•  $\left(1,\ 3\right)$  

•  $\left(2,\ 5\right)$  

•  $\left(3,\ 2\right)$  

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the following system:

 $2x-y=-1$  

 $y=x-1$  

•  $\left(-2,-3\right)$  

•  $\left(4,\ 5\right)$  

•  $\left(5,\ 3\right)$  

•  $\left(3,\ 4\right)$  

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6