Equations of Circles,midpoint,distance

Write the equation of a circle with center (7, 0) with radius 3.

• (x - 7)² + y² = 9
• x² + (y -7)² = 9
• (x - 7)² + y² = 3
• x² + (y -7)² = 3

Tags

CCSS.HSG.GPE.A.1

What are the coordinates of the center and the radius of the circle with equation:
(x - 4)² + (y - 3)² = 25 ?

• Center (4,3)
  Radius = 5 units
• Center (4,3)
  Radius = 25 units
• Center (-4,-3)
  Radius = 25 units
• Center (-4,-3)
  Radius = 5 units

Tags

CCSS.HSG.GPE.A.1

Write the standard equation of the circle with the given center and radius; center (0,0) and radius: 3

• x²+y²=4
• x²+y²=81
• x²+y²=9

Tags

CCSS.HSG.GPE.A.1

What is the center of the circle with equation x² + y² = 1?

• (1, 1)
• (0, 0)
• not enough information

Tags

CCSS.HSG.GPE.A.1

See Picture

• A
• B
• C

Tags

CCSS.HSG.GPE.A.1

See Picture

• A
• B
• C
• D

Tags

CCSS.HSG.GPE.A.1

What is the equation of the circle?

• (x+1)² + (y +1)² = 3
• (x+1)² + (y -1)² = 3
• (x+1)² + (y +1)² = 9
• (x-1)² + (y -1)² = 9

Tags

CCSS.HSG.GPE.A.1

Write the equation of a circle with center
(7, 0) with radius 3. 

• (x - 7)² + y² = 9
• x² + (y -7)² = 9
• (x - 7)² + y² = 3
• x² + (y -7)² = 3

Tags

CCSS.HSG.GPE.A.1

• A
• B
• C
• D

Tags

CCSS.HSG.GPE.A.1

What is the center of the circle with this equation is (x+2)²+(y-4)²=41?

• (2,-5)
• (-2,4)
• (2,-4)

Tags

CCSS.HSG.GPE.A.1