Hệ thức lượng trong tam giác thường

Authored by Quyền Nguyễn Trần

Mathematics

10th Grade

Used 317+ times

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9 questions

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MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$a^2=...^2+c^2-2bc\text{c}os\alpha$

$b$

$a$

$m_a$

$R$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$a^2=...^2+c^2-2bc\text{c}osA$

$b$

$a$

$m_a$

$R$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$b^2=...^2+c^2-2ac\text{c}osB$

$b$

$a$

$m_a$

$R$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$b^2=...^2+c^2-2ac\text{c}osB$

$b$

$a$

$m_a$

$R$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$c^2=a^2+b^2-2ab...$

$\text{c}osC$

$\text{c}osB$

$\sin B$

$\sin C$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$m_a^2=\frac{2\left(b^2+c^2\right)-a^2}{...}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\frac{a}{\sin A}=2...$

$R$

$b$

$c$

$\text{c}osA$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\frac{a}{\sin A}=\frac{...}{\sin B}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$...^2=\frac{2\left(a^2+b^2\right)-c^2}{4}$

$m_c$

$m_b$

$m_a$

$R$

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Hệ thức lượng trong tam giác thường

a2=...2+c2−2bccosαa^2=...^2+c^2-2bc\text{c}os\alphaa2=...2+c2−2bccosα

a2=...2+c2−2bccosAa^2=...^2+c^2-2bc\text{c}osAa2=...2+c2−2bccosA

b2=...2+c2−2accosBb^2=...^2+c^2-2ac\text{c}osBb2=...2+c2−2accosB

b2=...2+c2−2accosBb^2=...^2+c^2-2ac\text{c}osBb2=...2+c2−2accosB

c2=a2+b2−2ab...c^2=a^2+b^2-2ab...c2=a2+b2−2ab...

ma2=2(b2+c2)−a2...m_a^2=\frac{2\left(b^2+c^2\right)-a^2}{...}ma2​=...2(b2+c2)−a2​

asin⁡A=2...\frac{a}{\sin A}=2...sinAa​=2...

asin⁡A=...sin⁡B\frac{a}{\sin A}=\frac{...}{\sin B}sinAa​=sinB...​

...2=2(a2+b2)−c24...^2=\frac{2\left(a^2+b^2\right)-c^2}{4}...2=42(a2+b2)−c2​

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$a^2=...^2+c^2-2bc\text{c}os\alpha$

$a^2=...^2+c^2-2bc\text{c}osA$

$b^2=...^2+c^2-2ac\text{c}osB$

$b^2=...^2+c^2-2ac\text{c}osB$

$c^2=a^2+b^2-2ab...$

$m_a^2=\frac{2\left(b^2+c^2\right)-a^2}{...}$

$\frac{a}{\sin A}=2...$

$\frac{a}{\sin A}=\frac{...}{\sin B}$

$...^2=\frac{2\left(a^2+b^2\right)-c^2}{4}$