Specific Heat & Calorimetry

Specific Heat & Calorimetry

10th - 12th Grade

31 Qs

quiz-placeholder

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Specific Heat & Calorimetry

Specific Heat & Calorimetry

Assessment

Quiz

Chemistry

10th - 12th Grade

Practice Problem

Medium

NGSS
HS-PS3-4, HS-PS3-1, MS-PS3-4

+3

Standards-aligned

Created by

Jennifer McGarvie

Used 42+ times

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31 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What  is the formula to calculate heat energy required to raise the temperature of any substance?

Q = m Cp ∆T
Q = m Cp
Q =  ½ m v
m = Q Cp

Tags

NGSS.MS-PS1-4

NGSS.MS-PS3-4

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

There are four cups of hot cocoa. The cup sizes are shown. The temperature of the cocoa in each cup is 25 degrees celsius. Which cup has the MOST thermal energy?

Large cup (Trenta)
Small cup (Tall)
Venti
All three are the same temperature so they have same thermal energy

Tags

NGSS.HS-PS3-4

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

If the specific heat of water is 4,186 J/kg∙°C, how much heat is required to increase the temperature of 1.2 kg of water from 23 °C to 39 °C? 

-80,371.2 J
44,938.6 J
80,371.2 J
112,575.9 K

Tags

NGSS.HS-PS3-1

NGSS.HS-PS3-4

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What would be the effect on the particles if more heat is supplied to the system?

They would slow down
They would stop moving
They would speed up
There would be no effect

Tags

NGSS.HS-PS1-5

NGSS.HS-PS3-4

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

A sample of iron receives 50.J of heat energy that raises the temperature of the iron 25.0°C. If iron has a specific heat of  0.10 J/g°C, what is the mass of the iron sample?

25 g
30 g
20 g
50 g

Tags

NGSS.HS-PS3-1

NGSS.HS-PS3-4

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

The specific heat is the amount of energy needed to raise the temperature one degree Celsius of 1 gram of a substance.

True
False

Tags

NGSS.MS-PS1-4

NGSS.MS-PS3-4

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Using the heat equation, what would the formula look like if we were solving for change in temperature?

Q m = ∆T Cp
Q / (m Cp)  =  ∆T
Q m / Cp  =  ∆T
m c Q  =  ∆T

Tags

NGSS.HS-PS3-1

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