Solving Logarithmic and Exponential Equations

• A
• B
• C
• D

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CCSS.HSF.LE.A.4

CCSS.HSF.LE.A.1

• A
• B
• C
• D

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CCSS.HSF.BF.B.5

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• B
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• D

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CCSS.HSA.REI.A.1

3^{2x – 6}  = 81

• x = log 4
• x = 5
• x = 4
• x = -1

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CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

log₅ (2x - 3)² = 6

• x = 128
•  x = 64
• x = 4
• x = 14

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CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

This question is SLIGHTLY a challenge but you should all be able to do it!! 
log x - log 8 = 3

• x = 1000
• x = 800
• x = 8000
• x = 100

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CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

CCSS.HSA.CED.A.1

Using the change of base rule, what is this logarithm equivalent to?

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CCSS.HSF.BF.B.5

Solve the equation for x (hint: simplify first)

• 458.38
• 25
• 3,051,757,813
• -0.845

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CCSS.HSF.BF.B.5

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

Re-write in log form 2⁶=64

• log₂6=64
• log₂64=6
• log₆₄2=6
• log₆₄6=2

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CCSS.HSF.BF.B.5

Rewrite log_pt = m in exponential form.

• p^t = m
• t^m = p
• m^t = p
• p^m = t

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CCSS.HSF.BF.B.5