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Writing Trig Equations from Graphs No Phase Shift

Authored by Donald York

Mathematics

10th - 12th Grade

CCSS covered

Used 747+ times

Writing Trig Equations from Graphs No Phase Shift
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9 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Which is a correct equation for the graph shown?

y=2sin⁡xy=2\sin x

y=sin⁡2xy=\sin2x

y=cos⁡2xy=\cos2x

y=sin⁡(12x)y=\sin\left(\frac{1}{2}x\right)

Tags

CCSS.HSF-IF.C.7E

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Which is a correct equation for the graph shown?

y=cos⁡(12x)y=\cos\left(\frac{1}{2}x\right)

y=sin⁡(12x)y=\sin\left(\frac{1}{2}x\right)

y=cos⁡2xy=\cos2x

y=12cos⁡(x)y=\frac{1}{2}\cos\left(x\right)

Tags

CCSS.HSF-IF.C.7E

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Which is a correct equation for the graph shown?

y=3sin⁡(πx)y=3\sin\left(\pi x\right)

y=πsin⁡(3x)y=\pi\sin\left(3x\right)

y=sin⁡(πx)+3y=\sin\left(\pi x\right)+3

y=−3cos⁡(πx)y=-3\cos\left(\pi x\right)

Tags

CCSS.HSF-IF.C.7E

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Which is a correct equation for the graph shown?

y=−2cos⁡(π2x)y=-2\cos\left(\frac{\pi}{2}x\right)

y=2cos⁡(π2x)y=2\cos\left(\frac{\pi}{2}x\right)

y=−2sin⁡(2πx)y=-2\sin\left(2\pi x\right)

y=−2cos⁡(2πx)y=-2\cos\left(2\pi x\right)

Tags

CCSS.HSF-IF.C.7E

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Which is a correct equation for the graph shown?

y=−4sin⁡x+2y=-4\sin x+2

y=−4cos⁡x+2y=-4\cos x+2

y=−4sin⁡(x+2)y=-4\sin\left(x+2\right)

y=4sin⁡(x)+2y=4\sin\left(x\right)+2

Tags

CCSS.HSF-IF.C.7E

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

Which is a correct equation for the graph shown?

y=12cos⁡(2x)−3y=\frac{1}{2}\cos\left(2x\right)-3

y=12cos⁡(12x)−3y=\frac{1}{2}\cos\left(\frac{1}{2}x\right)-3

y=12cos⁡(2x+3)y=\frac{1}{2}\cos\left(2x+3\right)

y=12sin⁡(2x)−3y=\frac{1}{2}\sin\left(2x\right)-3

Tags

CCSS.HSF-IF.C.7E

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

Which is a correct equation for the graph shown?

y=tan⁡2xy=\tan2x

y=2tan⁡xy=2\tan x

y=tan⁡x+2y=\tan x+2

y=−tan⁡2xy=-\tan2x

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