Solving Systems of Equations by Substitution

Solve this system of equations. 
y = 2x + 1
y = 4x - 1

• (1,3)
• (-1,-3)
• (-1,3)
• (3,1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

x + 2y = 2
x = -4y + 2

• (-3, 0)
• (0, 2)
• (-3, -2)
• (2, 0)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the solution to the system of equations? 
y = 3x - 8
y = 4 - x

• (3,1)
• (1,3)
• (-3,1)
• (3,-1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

y = -3x + 11
y = -6x - 13

• (-8, 35)
• (8, -13)
• (1, 8)
• (2, 13)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

y = 5x + 1
y = 3x + 13

• (6, 31)
• (31, 6)
• (4, 21)
• (2, 11)

Tags

TEKS.MATH.A.5C

y = -3x + 11
5x + y = 21

• (1, -5)
• (1, 5)
• (-4, 5)
• (5, -4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6