Geometria analityczna

$\left|AB\right|=\sqrt{\left(x_A-x_B\right)_{ }^2+\left(y_A+y_B\right)^2}$

$\left|AB\right|=\sqrt{\left(x_B-x_A\right)_{ }^2+\left(y_B-y_A\right)^2}$

$\left|AB\right|=\sqrt{\left(x_A-y_A\right)_{ }^2+\left(x_B-y_B\right)^2}$

$\left|AB\right|=\sqrt{\left(x_A+x_B\right)_{ }^2+\left(y_A+y_B\right)^2}$

$S=\left(\frac{x_A+x_B}{2},\frac{y_A+y_B}{2}\right)$

$S=\left(\frac{x_A-x_B}{2},\frac{y_A-y_B}{2}\right)$

$S=\left(\frac{x_A+y_A}{2},\frac{x_B+y_B}{2}\right)$

$S=\left(\frac{x_A}{2},\frac{y_B}{2}\right)$

$S=\left(1,5\right)$

$S=\left(4,6\right)$

$S=\left(2,3\right)$

$S=\left(3,1\right)$

$7$

$\sqrt{29}$

$29$

$\sqrt{3}$

 $S=\left(5,1\right)$  

 $S=\left(-5,-1\right)$  

 $S=\left(-5,1\right)$  

 $S=\left(7,-1\right)$  

 $25$  

 $-1$  

 $1$  

 $5$  

 $y=-2x+3$  

 $y=2x-1$  

 $y=\frac{1}{2}x+2$  

 $y=-\frac{1}{2}x+6$  

 $\left(x-5\right)^2+\left(y-3\right)^2=4$  

 $\left(x+5\right)^2+\left(y-3\right)^2=4$  

 $\left(x+5\right)^2+\left(y-3\right)^2=16$  

 $\left(x-5\right)^2-\left(y+3\right)^2=16$  

m = 0

m = 4

m = 3

m = 2

y = -3x + 2

y = 3x - 2

y = 3x

y = -1/3x - 2