เขียน z = 1 − 3 i 1-\sqrt{3}i 1 − 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> i ในรูปเชิงขั้ว

2 ( cos ⁡ 300 ° + i sin ⁡ 300 ° ) 2\left(\cos\ 300\degree\ +\ i\ \sin\ 300\degree\right) 2 ( cos 3 0 0 ° + i sin 3 0 0 ° )

2 ( cos ⁡ 330 ° + i sin ⁡ 330 ° ) 2\left(\cos\ 330\degree\ +\ i\ \sin\ 330\degree\right) 2 ( cos 3 3 0 ° + i sin 3 3 0 ° )

เขียน z = − 4 + 4 3 i -4\ +\ 4\sqrt{3}i − 4 + 4 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> i ในรูปเชิงขั้ว

8 ( cos ⁡ 120 ° + i sin ⁡ 120 ° ) 8\left(\cos\ 120\degree\ +\ i\ \sin\ 120\degree\right) 8 ( cos 1 2 0 ° + i sin 1 2 0 ° )

8 ( cos ⁡ 240 ° + i sin ⁡ 240 ° ) 8\left(\cos\ 240\degree\ +\ i\ \sin\ 240\degree\right) 8 ( cos 2 4 0 ° + i sin 2 4 0 ° )

เขียน z = − 2 − 2 3 i -2-2\sqrt{3}i − 2 − 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> i ในรูปเชิงขั้ว

4 ( cos ⁡ 240 ° + i sin ⁡ 240 ° ) 4\left(\cos\ 240\degree\ +\ i\ \sin\ 240\degree\right) 4 ( cos 2 4 0 ° + i sin 2 4 0 ° )

4 ( cos ⁡ 120 ° + i sin ⁡ 120 ° ) 4\left(\cos\ 120\degree+i\ \sin\ 120\degree\right) 4 ( cos 1 2 0 ° + i sin 1 2 0 ° )

เขียน z = 4 − 4 3 i 4-4\sqrt{3}i 4 − 4 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> i ในรูปเชิงขั้ว

4 ( cos ⁡ 300 ° + i sin ⁡ 300 ° ) 4\left(\cos\ 300\degree\ +\ i\ \sin\ 300\degree\right) 4 ( cos 3 0 0 ° + i sin 3 0 0 ° )

4 ( cos ⁡ 240 ° + i sin ⁡ 240 ° ) 4\left(\cos\ 240\degree\ +\ i\ \sin\ 240\degree\right) 4 ( cos 2 4 0 ° + i sin 2 4 0 ° )

เขียน z = 3 + i \sqrt{3}+i 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> + i ในรูปเชิงขั้ว

2 ( cos ⁡ 30 ° + i sin ⁡ 30 ° ) 2\left(\cos\ 30\degree\ +\ i\ \sin\ 30\degree\right) 2 ( cos 3 0 ° + i sin 3 0 ° )

2 ( cos ⁡ 60 ° + i sin ⁡ 60 ° ) 2\left(\cos\ 60\degree\ +\ i\ \sin\ 60\degree\right) 2 ( cos 6 0 ° + i sin 6 0 ° )

เขียน z = 2 3 − 2 i 2\sqrt{3}-2i 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 2 i ในรูปเชิงขั้ว

4 ( cos ⁡ 330 ° + i sin ⁡ 330 ° ) 4\left(\cos\ 330\degree\ +\ i\ \sin\ 330\degree\right) 4 ( cos 3 3 0 ° + i sin 3 3 0 ° )

4 ( cos ⁡ 300 ° + i sin ⁡ 300 ° ) 4\left(\cos\ 300\degree\ +\ i\ \sin\ 300\degree\right) 4 ( cos 3 0 0 ° + i sin 3 0 0 ° )

เขียน z = 1 - i ในรูปเชิงขั้ว

2 ( cos ⁡ 315 ° + i sin ⁡ 315 ° ) \sqrt{2}\left(\cos\ 315\degree\ +\ i\ \sin\ 315\degree\right) 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> ( cos 3 1 5 ° + i sin 3 1 5 ° )

2 2 ( cos ⁡ 135 ° + i sin ⁡ 135 ° ) 2\sqrt{2}\left(\cos\ 135\degree\ +\ i\ \sin\ 135\degree\right) 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> ( cos 1 3 5 ° + i sin 1 3 5 ° )

จำนวนเชิงซ้อนในรูปเชิงขั้ว

Authored by คมไผ่ พรรณา

Mathematics

1st - 12th Grade

Used 49+ times

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25 questions

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MULTIPLE CHOICE QUESTION

1 min • 1 pt

ให้ z = 2 + 2i จงหา |z|

2 $\sqrt{2}$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

ให้ z = 2 + 2i จงหา Arg (z)

$30\degree$

$45\degree$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

ให้ z = 2 + 2i แล้ว z ในรูปเชิงขั้วตรงกับข้อใด

$2\sqrt{2}\left(\cos\ 45\degree+\ i\ \sin\ 45\degree\right)$

$4\left(\cos\ 30\degree\ +\ i\ \sin\ 30\degree\right)$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

ให้ z = $1\ -\ \sqrt{3}i$ จงหา |z|

MULTIPLE CHOICE QUESTION

1 min • 1 pt

ให้ z = $1-\sqrt{3}i$ จงหา Arg (z)

$300\degree$

$330\degree$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

เขียน z = $1-\sqrt{3}i$ ในรูปเชิงขั้ว

$2\left(\cos\ 330\degree\ +\ i\ \sin\ 330\degree\right)$

$2\left(\cos\ 300\degree\ +\ i\ \sin\ 300\degree\right)$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

ให้ z = $-4+4\sqrt{3}i$ จงหา |z|

MULTIPLE CHOICE QUESTION

1 min • 1 pt

ให้ z = $-4+4\sqrt{3}i$ จงหา Arg (z)

$240\degree$

$120\degree$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

เขียน z = $-4\ +\ 4\sqrt{3}i$ ในรูปเชิงขั้ว

$8\left(\cos\ 120\degree\ +\ i\ \sin\ 120\degree\right)$

$8\left(\cos\ 240\degree\ +\ i\ \sin\ 240\degree\right)$

10.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

ให้ z = $-2-2\sqrt{3}i$ จงหา |z|

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จำนวนเชิงซ้อนในรูปเชิงขั้ว

ให้ z = 2 + 2i จงหา |z|

ให้ z = 2 + 2i จงหา Arg (z)

ให้ z = 2 + 2i แล้ว z ในรูปเชิงขั้วตรงกับข้อใด

ให้ z = 1 − 3i1\ -\ \sqrt{3}i1 − 3​i จงหา |z|

ให้ z = 1−3i1-\sqrt{3}i1−3​i จงหา Arg (z)

เขียน z = 1−3i1-\sqrt{3}i1−3​i ในรูปเชิงขั้ว

ให้ z = −4+43i-4+4\sqrt{3}i−4+43​i จงหา |z|

ให้ z = −4+43i-4+4\sqrt{3}i−4+43​i จงหา Arg (z)

เขียน z = −4 + 43i-4\ +\ 4\sqrt{3}i−4 + 43​i ในรูปเชิงขั้ว

ให้ z = −2−23i-2-2\sqrt{3}i−2−23​i จงหา |z|

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Discover more resources for Mathematics

ให้ z = $1\ -\ \sqrt{3}i$ จงหา |z|

ให้ z = $1-\sqrt{3}i$ จงหา Arg (z)

เขียน z = $1-\sqrt{3}i$ ในรูปเชิงขั้ว

ให้ z = $-4+4\sqrt{3}i$ จงหา |z|

ให้ z = $-4+4\sqrt{3}i$ จงหา Arg (z)

เขียน z = $-4\ +\ 4\sqrt{3}i$ ในรูปเชิงขั้ว

ให้ z = $-2-2\sqrt{3}i$ จงหา |z|