SIMULASI PTS MAT MINAT 2020 ( Bab Lingkaran)

SIMULASI PTS MAT MINAT 2020 ( Bab Lingkaran)

11th Grade

36 Qs

quiz-placeholder

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SIMULASI PTS MAT MINAT 2020 ( Bab Lingkaran)

SIMULASI PTS MAT MINAT 2020 ( Bab Lingkaran)

Assessment

Quiz

Mathematics

11th Grade

Medium

Created by

Falentinus Wegig

Used 12+ times

FREE Resource

36 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 x2+y2+4x6y3=0x^2+y^2+4x-6y-3=0  Jari jari lingkaran tersebut adalah ....

2

3

4

16

20

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 x2+y22x4y+2=0x^2+y^2-2x-4y+2=0  titik pusat lingkaran tersebut adalah ...

(1,1)

(3,2)

(-1,2)

(1,2)

(2,1)

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Persamaan lingkaran yang berpusat di (3,2) dan jari - jarinya 4 adalah ...

x2+y26x+4y3=0x^2+y^2-6x+4y-3=0

x2+y26x4y3=0x^2+y^2-6x-4y-3=0

x2+y2+6x4y3=0x^2+y^2+6x-4y-3=0

x2+y26x4y+3=0x^2+y^2-6x-4y+3=0

x2+y2+4x6y3=0x^2+y^2+4x-6y-3=0

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Persamaan lingkaran yang berpusat di (2,4) dan melalui titik (10,-2) adalah ....

x2+y24x8y80=0x^2+y^2-4x-8y-80=0

x2+y2+4x8y80=0x^2+y^2+4x-8y-80=0

x2+y24x8y60=0x^2+y^2-4x-8y-60=0

x2+y2+4x+8y80=0x^2+y^2+4x+8y-80=0

x2+y2+4x+8y+80=0x^2+y^2+4x+8y+80=0

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Persamaan lingkaran yang berpusat di (3,-3) dan menyinggung sumbu x positif dan sumbu y negatif adalah ...

x2+y26x+6y9=0x^2+y^2-6x+6y-9=0

x2+y2+6x6y+9=0x^2+y^2+6x-6y+9=0

x2+y26x+6y+9=0x^2+y^2-6x+6y+9=0

x2+y26x6y9=0x^2+y^2-6x-6y-9=0

x2+y2+6x+6y+9=0x^2+y^2+6x+6y+9=0

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Persamaan lingkaran yang berpusat di (-3,2) dan menyinggung garis 3x-4y-8=0 adalah ....

(x+3)2+(y2)2=15\left(x+3\right)^2+\left(y-2\right)^2=15

(x+3)2+(y2)2=25\left(x+3\right)^2+\left(y-2\right)^2=25

(x3)2+(y2)2=15\left(x-3\right)^2+\left(y-2\right)^2=15

(x3)2+(y2)2=25\left(x-3\right)^2+\left(y-2\right)^2=25

(x+3)2+(y+2)2=15\left(x+3\right)^2+\left(y+2\right)^2=15

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Persamaan lingkaran dengan titik A (2,4) dan titik B (6,6) dengan AB adalah diameter adalah ....

x2+y28x10y+36=0x^2+y^2-8x-10y+36=0

x2+y2+8x10y+36=0x^2+y^2+8x-10y+36=0

x2+y2+8x+10y+36=0x^2+y^2+8x+10y+36=0

x2+y210x8y+36=0x^2+y^2-10x-8y+36=0

x2+y2+10x+8y36=0x^2+y^2+10x+8y-36=0

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