Linear Equations - Spring Benchmark Review

Graph. y = 2/3x - 3

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CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

Graph. 3x + 4y = 12

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Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

Graph. y = -4

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Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

Write the equation of the line with a slope of -5/4 and a y-intercept of 2.

• y = -1/4x + 2

• y = 2x - 5/4

• y = 1/4x + 2

• y = -5/4x + 2

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

Write the equation of the line passes through the point (3,-1) and has a slope of 2.

• y = 3x - 1

• y = 2x - 5

• y = 2x - 7

• y = -x + 3

Tags

CCSS.HSA.CED.A.2

CCSS.HSG.GPE.B.5

Write the equation of the line passes through the point (2,1) and has a slope = 4.

• y = 3x - 2

• y = 4x - 7

• y = 4x + 7

• y = 3x + 3

Tags

CCSS.HSA.CED.A.2

CCSS.HSF.LE.A.2

CCSS.HSG.GPE.B.5

CCSS.HSF.BF.A.1

Given the table, write the equation in the slope-intercept form.

• y = 1/3x + 6
• y = 3x + 6
• y = 2x + 6
• y = 1/2x + 6

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

Write the equation in slope-intercept form: 5x - 2y = 12

• y = 5/2x - 6
• y = -5/2x - 6
• y = 5x +12
• y = -5x + 12

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

Given the equation, 3x - 2y = -10, identify the slope and the y-intercept.

• slope: -3, y-intercept: -10
• slope: -2/3, y-intercept: -5
• slope: 3/2, y-intercept: 5
• slope: -3/2, y-intercept: 5

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

Write the linear equation of a line that passes through (2,5) and (2, 9).

• y = 0
• x = 0
• y = 2
• x = 2

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10