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(ACT:1) Hypothesis Testing for the Mean (Small Samples)

Authored by Alexis Caducio

Mathematics

11th Grade

CCSS covered

Used 35+ times

(ACT:1) Hypothesis Testing for the Mean (Small Samples)
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10 questions

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1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A used car dealer says that the mean price of a 2008 Honda CR-V is at least $20,500. You suspect this claim is incorrect and find that a random sample of 14 similar vehicles has a mean price of $19,850 and a standard deviation of $1084. Is there enough evidence to reject the dealer’s claim at α = 0.05? Assume the population is normally distributed. 

State the hypothesis of the given problem.

Ho:  µ  \ge  20,500
H1:  µ <<  20,500

Ho:  µ  \le  20,500
H1:  µ >>  20,500

Ho:  µ  >>  20,500
H1:  µ \le  20,500

Ho:  µ  <<  20,500
H1:  µ \ge  20,500

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A used car dealer says that the mean price of a 2008 Honda CR-V is at least $20,500. You suspect this claim is incorrect and find that a random sample of 14 similar vehicles has a mean price of $19,850 and a standard deviation of $1084. Is there enough evidence to reject the dealer’s claim at α = 0.05? Assume the population is normally distributed. 

What is the value of the critical region?

Critical region = −1.771

Critical region = 1.771

Critical region = −2.160

Critical region = 2.160

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A used car dealer says that the mean price of a 2008 Honda CR-V is at least $20,500. You suspect this claim is incorrect and find that a random sample of 14 similar vehicles has a mean price of $19,850 and a standard deviation of $1084. Is there enough evidence to reject the dealer’s claim at α = 0.05? Assume the population is normally distributed. 

Find the t-score for the sample.

t-score−2.244

t-score = 2.244

t-score = 2.255

t-score = −2.255

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A used car dealer says that the mean price of a 2008 Honda CR-V is at least $20,500. You suspect this claim is incorrect and find that a random sample of 14 similar vehicles has a mean price of $19,850 and a standard deviation of $1084. Is there enough evidence to reject the dealer’s claim at α = 0.05? Assume the population is normally distributed. 

What is the decision rule and conclusion on the given problem?

t value is in the rejection region, therefore we reject H0: there is enough evidence at the 5% significance level to accept the claim.

t value is not in the rejection region, therefore we fail to reject H0: there is no enough evidence at the 5% significance level to reject this claim.

t value is in the rejection region, therefore we reject H0: there is no enough evidence at the 5% significance level to accept the claim.

t value is in the rejection region, therefore we fail to reject H0: there is enough evidence at the 5% significance level to reject this claim.

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A manufacturer claims that his tires last at least 40,000

miles. A test on 25 tires reveals that the mean life of a tire is 39,750 miles, with a standard deviation of 387 miles. Test the Manufacturer’s claim at α = .01.


What is the statement of the hypothesis of the given problem?

Ho: µ \ge 40,000
H1: µ << 40,000

Ho: µ >> 40,000
H1: µ \le 40,000

Ho: µ << 40,000
H1: µ \ge 40,000

Ho: µ \le 40,000
H1: µ >> 40,000

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A manufacturer claims that his tires last at least 40,000 miles. A test on 25 tires reveals that the mean life of a tire is 39,750 miles, with a standard deviation of 387 miles.

Test the Manufacturer’s claim at α = .01.


What is the critical region?

Critical region = -2.492

Critical region = 2.492

Critical region = -2.797

Critical region = 2.797

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A manufacturer claims that his tires last at least 40,000 miles. A test on 25 tires reveals that the mean life of a tire is 39,750 miles, with a standard deviation of 387 miles.

Test the Manufacturer’s claim at α = .01.


What is the t score for the sample?

t-score = 461.88

t-score = -461.88

t-score = -461.86

t-score = 461.86

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