Solve Quadratics by Factoring

x²+4x-32=0

• x= -8, 4

• x= 8, -4

• x= -8, -4

Tags

CCSS.HSA-REI.B.4B

x²-14x-51=0

• x= 17, -3

• x= -17, 3

• x= -17, -3

Tags

CCSS.HSA-REI.B.4B

x²=18x-81

• x= -9, -9

• x= 9, 9

• x= -9, 9

Tags

CCSS.HSA-REI.B.4B

x²-7x=0

• x= 0, -7

• x= 0, 7

Tags

CCSS.HSA-REI.B.4B

81x²=25

• x= 5/9, -5/9

• x= -5/9, -5/9

• x= 5/9, 5/9

Tags

CCSS.8.EE.A.2

What are the factors AND solutions of x² + 2x – 3 = 0

• (x - 2)(x + 1); x=2, x=-1
• (x + 1)(x - 3); x=-1, x=3
• (x + 2)(x - 1); x=-2, x=1
• (x - 1)(x + 3); x=1, x=-3

Tags

CCSS.HSA-REI.B.4B

Given the factors below what is the quadratic equation?

• y= 2x² -5x +3
• y= 2x² +7x -3
• y= 2x² -5x -3
• y= 2x² -7x -3

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

Solve for X:

(x-5)(x+6)=0

• {5,5 }

• { -5,-5 }

• { -5,-6 }

• {5,-6 }

Tags

CCSS.HSA-REI.B.4B

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

Tags

CCSS.HSA-REI.B.4B

Which equation matches these solutions? x=5,-7

• (x+5)(x-7)=0
• (x-5)(x+7)=0
• (x+5)(x+7)=0
• (x-5)(x-7)=0

Tags

CCSS.HSA-REI.B.4B