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Conics: Equation of a Hyperbola

Mathematics

10th - 12th Grade

CCSS covered

Used 1+ times

Conics:  Equation of a Hyperbola
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16 questions

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1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the equation describing the relationship between dimensions and foci of a hyperbola?

c2 = a2 + b2
c2 = a2 - b2
4p
(x-h)2 + (y-k)2 = r2

Tags

CCSS.HSG.GPE.A.3

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Which way does the hyperbola open?

up and down

left or right

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

The equation of the hyperbola, in standard form is . . .

A

B

C

D

Tags

CCSS.HSG.GPE.A.3

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

What are the vertices of the hyperbola?

(0, 5) and (0, -5)
(5, 0) and (-5, 0)
(0, 25) and (-25, 0)
(0, 0) and (0, 5)

Tags

CCSS.HSG.GPE.A.3

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What is a and b?

a = 1, b = 2

a = 9, b = 4

a = 3, b = 2

a = 25, b = 10

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.SSE.A.1

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

In which direction does the hyperbola open?

up and down

left and right

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Write in standard form,  x24y2+10x+32y75=0x^2-4y^2+10x+32y-75=0  

 \frac{\left(y-4\right)^2}{36}-\frac{\left(x+5\right)^2}{9}=1  

 (y4)29(x+5)236=1\frac{\left(y-4\right)^2}{9}-\frac{\left(x+5\right)^2}{36}=1  

 (y4)29(x5)236=1\frac{\left(y-4\right)^2}{9}-\frac{\left(x-5\right)^2}{36}=1  

 (x+5)236(y4)29=1\frac{\left(x+5\right)^2}{36}-\frac{\left(y-4\right)^2}{9}=1  

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