Kimia: Sebatian Karbon (Alkena)

Persamaan di bawah menunjukkan tindak balas alkena

The equation below shows a reaction of alkene

CH₃CH=CH₂ + Y → CH₃CH₂CH₂Br

Antara yang berikut, yang manakah Y?

Which of the following is Y?

• Bromin, Br2

  Bromine, Br₂

• Hidrogen bromida, HBr

  Hydrogen bromide, HBr

• Natrium bromida, NaBr

  Sodium bromide, NaBr

• Magnesium bromida, MgBr2

  Magnesium bromide, MgBr₂

Manakah formula molekul bagi hidrokarbon tak tepu?

Which of the molecular formula is unsaturated hydrocarbon?

• C₃H₆

• C₄H₁₀

• C₅H₁₂

• C₆H₁₄

Etena dapat dibezakan daripada etana kerana etena dapat

Ethene can be differentiate from ethane because ethene can

• terlarut campur dengan air manakala etana tidak

  miscrible in water whereas ethane cannot

• terbakar dalam udara manakala etana tidak

  burn in air whereas ethane cannot

• bertindak balas dengan ester manakala etana tidak

  react with alcohol to produce ester whereas ethane cannot

• melunturkan warna perang air bromin pada suhu bilik manakala etana tidak

  decolourised the brown colour of bromine water at room temperature whereas ethane cannot

Rajah di bawah menunjukkan formula molekul bagi dua sebatian hidrokarbon.

Diagram below shows molecular formulae of two hydrocarbon compounds.

Compound A

C4H8

Compound B

C4H10

Antara berikut, yang manakah benar tentang sebatian A dan B?

Which of the following is true about compounds A and B?

• Sebatian A menghasilkan lebih jelaga apabila terbakar dalam udara

  Compound A produces more soot when burnt in air

• Sebatian B menyahwarnakan warna perang air bromine, sebatian A tidak

  Compound B decolorizes brown bromine water, compound A does not

• Sebatian A adalah hidrokarbon tepu, sebatian B adalah hidrokarbon tak tepu

  Compound A is a saturated hydrocarbon, compound B is an unsaturated hydrocarbon

• Sebatian A mengalami tindak balas penukargantian, sebatian B mengalami tindak balas penambahan

  Compound A undergoes substitution reaction, compound B undergoes addition reaction

Nama IUPAC bagi sebatian yang terhasil antara tindak balas propena dan bromin ialah

The IUPAC name of the compound formed by the reaction between propene and bromine is

• Bromopropana

  Bromopropane

• 1,1-dibromopropana

  1,1-dibromopropane

• 1,2-dibromopropana

  1,2-dibromopropane

• 1,3-dibromopropana

  1,3-dibromopropane

Sifat-sifat yang manakah sama bagi propana dan propena?

Which properties of propane and propene are the same?

• Larut dalam air

  Soluble in water

• menyahwarnakan warna perang air bromin

  Decolourise brown colour of bromine water

• Terbakar lengkap dalam udara menghasilkan karbon dioksida dan air

  Burn completely in air to produce carbon dioxide and water

• Menyahwarnakan warna ungu larutan kalium manganat (VII) berasid

  Decolourise purple colour of acidified potassium manganate (VII) solution

Apakah nama proses penyediaan etanol dalam industri?

What is the name of the process for the preparation of ethanol in industry?

• Pengoksidaan

  Oxidation

• Penghidratan

  Hydration

• Pendehidratan

  Dehydration

• Penghidrogenan

  Hydrogenation

Apakah nama sebatian itu berdasarkan penamaan IUPAC?

What is the name of the compound based on IUPAC nomenclature?

• Pent-2-ena

  Pent-2-ene

• 2-metilbut-1-ena

  2-methylbut-1-ene

• 2-metilbut-2-ena

  2-methylbut-2-ene

• 3-metilbut-2-ena

  3-methylbut-2-ene

• I dan II sahaja

• III dan IV sahaja

• I, II dan III sahaja

• II, III dan IV sahaja

Formula kimia bagi butena ialah C4H8. Tentukan jisim molekul relatif bagi alkohol yang mempunyai bilangan atom karbon yang sama dengan butena.

The chemical formula of butene is C4H8.

Determine the relative molecular mass for the alcohol that same number of carbon with butene.

[ Jisim atom relatif H=1, C=12, O=16 ]

[ Relative atomic mass of H=1, C=12, O=16 ]

• 30

• 48

• 56

• 74