Six Trigonometric Ratios

Give the ratio for $\tan\theta$  

•  $\frac{adjacent}{opposite}$  

•  $\frac{opposite}{adjacent}$  

•  $\frac{adjacent}{hypotenuse}$  

•  $\frac{opposite}{hypotenuse}$  

Tags

CCSS.HSG.SRT.C.6

Give the ratio for  $\cos\theta$  

•  $\frac{adjacent}{hypotenuse}$  

•  $\frac{opposite}{adjacent}$  

•  $\frac{adjacent}{opposite}$  

•  $\frac{opposite}{hypotenuse}$  

Tags

CCSS.HSG.SRT.C.6

What is the correct ratio?

• $\frac{6}{10}$

• $\frac{6}{8}$

• $\frac{8}{10}$

• $\frac{8}{6}$

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

What is the correct equation to solve for x?

• $\tan45\degree=\frac{x}{13}$

• $\cos45\degree=\frac{x}{13}$

• $\sin45\degree=\frac{13}{x}$

• $\sin\ 45\degree=\frac{x}{13}$

Tags

CCSS.HSG.SRT.C.6

What is the length of the hypotenuse side?

• 8

• 15

• 17

Tags

CCSS.8.G.B.7

Choose the correct ratio.

• $\sin\ Z=\frac{5}{13}$

• $\sin\ X=\frac{5}{13}$

• $\cos\ X=\frac{12}{13}$

• $\tan\ Z=\frac{12}{5}$

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

What is the correct ratio for tan A?

• $\frac{20}{12}$

• $\frac{12}{20}$

• $\frac{12}{16}$

• $\frac{16}{12}$

Tags

CCSS.HSG.SRT.C.6

Identify the trigonometric ratio that may be used to find the marked unknown side.

•  $\sin\ 29\degree=\frac{x}{91}$  

•  $\tan\ 29\degree\ =\ \frac{91}{x}$ 

•  $\cos\ 29\degree\ =\ \frac{x}{91}$ 

•  $\tan\ 29\degree=\ \frac{x}{91}$ 

Tags

CCSS.HSG.SRT.C.6

What is the formula for secant?

• $\sec=\frac{adjacent}{opposite}$

• $\sec=\frac{hypotenuse}{opposite}$

• $\sec=\frac{opposite}{hypotenuse}$

• $\sec=\frac{hypotenuse}{adjacent}$

Tags

CCSS.HSG.SRT.C.6

What is the formula for cosecant?

•  $\csc=\frac{adjacent}{opposite}$  

•  $\csc=\frac{hypotenuse}{opposite}$  

•  $\csc=\frac{opposite}{hypotenuse}$  

•  $\csc=\frac{hypotenuse}{adjacent}$  

Tags

CCSS.HSG.SRT.C.6