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Probability Quiz 9.06

Authored by Alexander Kuritzky

Mathematics

10th - 11th Grade

Used 1+ times

Probability Quiz 9.06
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6 questions

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1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

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Given that the practice time was 3 pointers, determine the exact probability that Bradley wins the next match.

P(3 pointers | Bradley wins) =  1523\frac{15}{23}  

P(3 pointers | Bradley wins) =  59\frac{5}{9}  

P(Bradley wins | 3 pointers ) =  1523\frac{15}{23}  

P(Bradley wins | 3 pointers) =  59\frac{5}{9}  

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

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A student response is selected at random from the results. State the exact probability the student response is from a freshman, given the student prefers to watch comedy shows on television.

.196

 946\frac{9}{46} 

.446

 54121\frac{54}{121} 

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

A student response is selected at random from the results. State the exact probability the response is from a student who is a freshman and prefers to watch reality shows on television.

P(freshman and prefer reality tv) = 103536\frac{103}{536} 

P(prefer reality tv | freshman) = 103260\frac{103}{260} 

P(freshman | prefer reality tv) = 103202\frac{103}{202} 

P(freshman and prefer reality tv) = 103379\frac{103}{379} 

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

There is a spinner with 15 equal areas, numbered 1 through 15. If the spinner is spun one time, what is the probability that the result is either a multiple of 3 or a multiple of 4?

P(multiple of 3 and multiple of 4) = 115\frac{1}{15} 

P(multiple of 3 or multiple of 4) = 115\frac{1}{15} 

P(multiple of 3 and multiple of 4) = 715\frac{7}{15} 

P(multiple of 3 or multiple of 4) = 715\frac{7}{15} 

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

In a virtual class of 26 students, 9 are in their pajamas and 6 are on their phones. There are 13 students who are not in their pajamas or on their phones. What is the probability that a student is in their pajamas given they are not on their phone?

P(not on phone | in pajamas) = 79\frac{7}{9}

P(in pajamas | not on phone) = 79\frac{7}{9}

P(in pajamas | not on phone) = 720\frac{7}{20}

P(not on phone | in pajamas) = 720\frac{7}{20}

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A fitness instructor holds online workout classes. The probability he does squats is 0.44 and the probability he does burpees is 0.57. The probability he doesn't do squats or burpees 0.32. What is the probability he does squats given he doesn't do burpees? Round your answer to the nearest thousandth.

P(squats | no burpees) = 0.250

P(squats | no burpees) = 0.256

P(no burpees | squats) = 0.256

P(no burpees | squats) = 0.250

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